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  3. Data analysis

Data analysis

How to record raw data with uncertainties, process them, draw and interpret graphs, linearise a relationship and find a gradient with its uncertainty, with a fully worked analysis.

  • IB Physics
  • Internal assessment
  • SL and HL

20 min readLast reviewed 14 Oct 2026

The Data analysis criterion assesses how the raw data are recorded, how they are processed into the quantities that answer the research question, and how uncertainties are handled throughout. A top-band analysis is clear (a reader can follow every step) and precise (every number has a unit, a sensible number of significant figures and an uncertainty), and the processing is correct and relevant to the question.

Analysis turns a table of readings into evidence. The usual route is raw data, then means and uncertainties, then a graph that tests the predicted relationship, then a gradient or intercept with its uncertainty, and finally a derived quantity that can be compared with theory or an accepted value. Each step is shown once, with an explanation, so that a moderator can check it.

Scope. The methods cover what IB Physics expects: uncertainties from instrument resolution and from repeated readings, propagation through sums, differences, products, quotients and powers, graphs with error bars, and gradients and intercepts with uncertainties from maximum and minimum lines. Statistical methods beyond these, such as standard deviations or regression uncertainties from software, may be used but must be explained.

What the criterion rewards

Strand

Middle band (3–4)

Top band (5–6)

Communication of recording and processing

Clear or precise

Clear and precise

Uncertainties

Considered, with some significant omissions or errors

Considered appropriately throughout

Processing relevant to the question

Carried out, with some significant omissions, inaccuracies or inconsistencies

Carried out appropriately and accurately

"Clear" refers to how easily the reader follows the work: labelled tables, a sample of each calculation, graphs that are easy to read. "Precise" refers to the numbers themselves: units, decimal places consistent with the instruments, significant figures matched to the uncertainty. A beautifully presented analysis with numbers to eight significant figures is clear but not precise.

Recording raw data

Definition

Raw data are the measurements exactly as read from the instruments, before any calculation. Processed data are values calculated from them, such as means, derived quantities and their uncertainties.

Raw data go into a table as they are taken. A raw data table follows a few conventions that make it both clear and precise.

  • Each column heading gives the quantity, its unit and its uncertainty: "LL / m ± 0.002". The unit appears only in the heading, not after each number.

  • The independent variable is in the first column.

  • Every value in a column has the same number of decimal places, set by the resolution of the instrument. A balance reading to 0.01 g gives 12.30 g, not 12.3 g.

  • Repeated readings sit in adjacent columns ("Trial 1", "Trial 2", "Trial 3").

  • Qualitative observations are recorded too: "the ball skidded at 14°", "the reading drifted by 0.02 Ω while the clip was held".

Qualitative data

Not all useful data are numbers. Observations such as "the trolley wobbled on the track above 0.8 m s⁻¹", "condensation formed on the beaker below 10 °C" or "the oscillation died away after about 15 cycles" explain anomalies, set the limits of a range and give the evaluation specific evidence. They are recorded with the quantitative data, at the time they are seen, and referred to where they matter in the analysis.

The uncertainty of a single reading

Every reading has an absolute uncertainty, written with ±, that reflects how precisely it can be read. For a digital instrument the usual convention is ± one unit in the last digit displayed. For an analogue scale it is commonly taken as ± half the smallest division, although a larger value is justified when the reading is harder to judge (a moving needle, a meniscus, two ends of an object both read on a rule).

Instrument

Reading

Uncertainty

Reason

Digital ohmmeter

1.92 Ω

± 0.01 Ω

Last digit displayed

Metre rule, one end at the zero mark

0.300 m

± 0.001 m

Half a millimetre at each end, rounded up

Stopwatch, hand-timed

7.48 s

± 0.2 s

Reaction time dominates the 0.01 s resolution

Video at 240 frames per second

312 frames

± 2 frames

Judging the start and end frames

Liquid-in-glass thermometer, 1 °C divisions

45.5 °C

± 0.5 °C

Half the smallest division

Common mistake

Quoting the resolution as the uncertainty when another effect is larger. A stopwatch displays 0.01 s, but a person starting and stopping it has a reaction time of about 0.1–0.2 s at each end. The uncertainty is set by the larger effect, and the report should say which one that is.

The uncertainty from repeated readings

When repeated readings differ, the spread is a direct measure of the random uncertainty. A simple and widely accepted estimate is half the range:

Δx=xmax−xmin2Δx=2xmax​−xmin​​

The mean is the best estimate of the value, and it is quoted to the same decimal place as its uncertainty. For three readings of 1.85 Ω, 1.93 Ω and 1.98 Ω, the mean is 1.92 Ω and half the range is 0.065 Ω, so the result is 1.92±0.07 Ω1.92±0.07 Ω. If half the range is smaller than the uncertainty of a single reading, the reading uncertainty is used instead.

Tip

Uncertainties are rounded to one significant figure (occasionally two, if the first digit is 1), and the value is then rounded to the same decimal place. Writing 1.9167 ± 0.065 Ω suggests a precision that the data do not have; 1.92 ± 0.07 Ω does not.

Outliers

An outlier is a reading that lies far from the trend of the others. An outlier is never deleted silently. It is identified, a reason is looked for (a misread scale, a slipped clamp, a different setting), and the reading is repeated if possible. If it is excluded from the processing, the report says so and gives the justification; if no reason can be found, it is usually kept and its effect discussed. No statistical test is expected for this, but the decision must be explained.

Processing data

Processing turns raw readings into the quantities that answer the question. It includes means, derived quantities (speed from distance and time, resistance from pd and current, T2T2 or 1/d21/d2 for a linearised graph), and the uncertainty of each.

Propagating uncertainties

When a quantity is calculated from measured values, its uncertainty is found from theirs. The rules use absolute uncertainties (ΔxΔx) for sums and differences, and fractional uncertainties (Δx/xΔx/x) for products, quotients and powers.

Calculation

Rule

y=a+by=a+b or y=a−by=a−b

Δy=Δa+ΔbΔy=Δa+Δb

y=abcy=cab​

Δyy=Δaa+Δbb+ΔccyΔy​=aΔa​+bΔb​+cΔc​

y=any=an

Δyy=∣n∣ ΔaayΔy​=∣n∣aΔa​

y=kay=ka (kk exact)

Δy=k ΔaΔy=kΔa

Fractional uncertainties are often written as percentage uncertainties: a fractional uncertainty of 0.026 is a percentage uncertainty of 2.6%. Adding percentages is quick and makes it easy to see which measurement contributes most.

Worked example

The diameter of a wire is d=0.38±0.01 mmd=0.38±0.01 mm. Calculate its cross-sectional area A=πd2/4A=πd2/4 and the uncertainty in AA.

Show the solution
A=π(0.38×10−3)24=1.134×10−7 m2A​=4π(0.38×10−3)2​=1.134×10−7 m2​

Uncertainty. ππ and 4 are exact, so only dd contributes, and it is squared:

ΔAA=2×0.010.38=0.053=5.3%ΔA=0.053×1.134×10−7=0.06×10−7 m2AΔA​ΔA​=2×0.380.01​=0.053=5.3%=0.053×1.134×10−7=0.06×10−7 m2​

So A=(1.13±0.06)×10−7 m2A=(1.13±0.06)×10−7 m2. The squaring doubles the percentage uncertainty, so the diameter, small and hard to measure, dominates any result that depends on AA.

Squared and cubed quantities appear often in physics investigations, so identifying the measurement that is raised to a power is usually the first step in finding the largest source of uncertainty.

Showing the processing

The report shows one sample calculation of each type, with the numbers substituted and the units, followed by a table of all the processed values. Repeating the same calculation eight times uses space and words without adding anything.

Exam tip

Moderators check that the processing in the table matches the sample calculation. A mean that does not match its raw readings, or a column of uncertainties that appears with no explanation, counts as an inconsistency and pulls the mark down.

Graphs

A graph is the main tool for testing a relationship. It shows the trend, the scatter and any outliers at a glance, and its gradient and intercept carry the quantitative result.

Drawing a good graph

  • The independent variable goes on the horizontal axis and the dependent variable (or the processed quantity) on the vertical axis.

  • Axes are labelled with the quantity and unit in the form "quantity / unit": "RR / Ω", "1/d21/d2 / m⁻²".

  • Scales are chosen so that the data fill most of the graph, with sensible steps (1, 2, 5 or 10 units per division). The origin is included when the theory says the line should pass through it.

  • Error bars show the uncertainty of each point in each direction. If the bars in one direction are too small to draw, the report says so.

  • A line of best fit (or a smooth curve of best fit) is drawn through the trend, with points scattered evenly on both sides. Points are never joined dot to dot.

  • Several data sets on one graph are distinguished by different symbols and a key.

Graphs drawn with software are normal in a report. The software's trend line is acceptable as the best-fit line, but its equation must be interpreted, not just displayed: the gradient and intercept are quoted with units and with their uncertainties.

Using a spreadsheet

A spreadsheet makes processing fast and consistent: one formula, entered once and filled down a column, calculates every mean, every uncertainty and every transformed value in the same way. The report states which software was used and gives one sample calculation by hand, so that a reader can check the formula. Common functions include the mean (AVERAGE), the maximum and minimum of repeats (MAX, MIN) for half the range, and LN or POWER for transformed axes.

Spreadsheets can also add error bars from a column of uncertainties and draw a trend line. The maximum and minimum gradient lines are found by plotting two extra straight lines by eye, adjusting their gradients and intercepts until each one just passes through every error bar, and reading off the gradients. Some spreadsheets report a statistical uncertainty in the gradient (for example from LINEST); this can be quoted as well, if the report explains what it is, but it does not use the error bars and can differ from the maximum–minimum estimate.

Common mistake

Using a trend line with a high-order polynomial because it passes through every point. A sixth-order polynomial fits almost any data and means nothing physically. Fit only the relationship that the theory predicts, usually by linearising it, and judge the fit from the error bars.

Gradient and intercept with uncertainty

The gradient of the best-fit line is usually the key result. Its uncertainty comes from the error bars. Two further lines, the maximum and minimum gradient lines, are drawn through all the error bars: the steepest possible and the shallowest possible. The uncertainty in the gradient is then

Δm=mmax−mmin2Δm=2mmax​−mmin​​

The same lines give the uncertainty in the intercept, Δc=(cmax−cmin)/2Δc=(cmax​−cmin​)/2, taking the intercepts of the two lines. Some analyses use the difference between the best gradient and the maximum or minimum gradient instead; either method is acceptable if it is stated.

Graph of resistance R in ohms against length L in metres from 0 to 0.9 m. Eight points with vertical error bars of about ±0.06 Ω lie close to a straight best-fit line of gradient 4.31 Ω m⁻¹ with intercept about 0.22 Ω.Graph of resistance R in ohms against length L in metres from 0 to 0.9 m. Eight points with vertical error bars of about ±0.06 Ω lie close to a straight best-fit line of gradient 4.31 Ω m⁻¹ with intercept about 0.22 Ω.
Sample data. The best-fit line (black) and the steepest and shallowest lines through all the error bars (blue and orange, dashed). The positive intercept shows a resistance that does not depend on length.

The resistance graph shows the method on sample data. The error bars in length (±0.002 m) are too small to see at this scale, so the maximum and minimum lines are set by the resistance error bars. The best-fit gradient is 4.31 Ω m⁻¹, and the steepest and shallowest lines that still pass through every error bar have gradients of 4.47 Ω m⁻¹ and 4.16 Ω m⁻¹, so

m=4.31±4.47−4.162=4.31±0.16 Ω m−1≈4.3±0.2 Ω m−1m=4.31±24.47−4.16​=4.31±0.16 Ω m−1≈4.3±0.2 Ω m−1

Tip

Draw the maximum and minimum lines by pivoting a ruler about the centre of the data: from the bottom of the first error bar to the top of the last for the maximum, and the reverse for the minimum. Then check that each line still passes through every bar, and adjust if one is missed.

Interpreting a graph

The features of a graph each have a physical meaning, which the analysis states.

Feature

What it can show

Straight line through the origin

Direct proportionality

Straight line with an intercept

A linear relationship, or proportionality with a systematic offset

Gradient

A physical constant or a combination of constants, with units = (unit of y)/(unit of x)

Intercept

A quantity present when x = 0 (a lead resistance, a spring's own mass, a zero error)

Change in gradient

A change in behaviour, such as a material reaching its elastic limit

Area under the graph

A product of the two quantities, such as work from force against extension

An intercept that does not match the theory is evidence of a systematic error. If the intercept, with its uncertainty, does not include zero when theory predicts zero, the report says so and suggests a cause. In the resistance data the intercepts of the two lines are 0.15 Ω and 0.28 Ω, so the intercept is 0.22±0.07 Ω0.22±0.07 Ω, clearly not zero, which matches the resistance of the leads and clip contacts.

Linearising a relationship

Many relationships in physics are not straight lines, but they can be rearranged into the form y=mx+cy=mx+c by choosing what to plot. A straight line is much easier to judge by eye than a curve, it gives a gradient and intercept with uncertainties, and it tests the predicted relationship directly. Linearising is used only where theory predicts a form to test.

Definition

Linearisation is rearranging a predicted relationship into the form y=mx+cy=mx+c and plotting the corresponding quantities, so that the relationship appears as a straight line if it holds.

Predicted relationship

Plot y

against x

Gradient

Intercept

T=2πm/kT=2πm/k​

T2T2

mm

4π2/k4π2/k

0

I=k/d2I=k/d2

II

1/d21/d2

kk

0

v=gdv=gd​

v2v2

dd

gg

0

R=ρL/A+R0R=ρL/A+R0​

RR

LL

ρ/Aρ/A

R0R0​

y=kxny=kxn (nn unknown)

ln⁡ylny

ln⁡xlnx

nn

ln⁡klnk

A=A0e−λtA=A0​e−λt

ln⁡AlnA

tt

−λ−λ

ln⁡A0lnA0​

The light-intensity data show linearisation in action. Plotted directly, intensity against distance falls along a curve.

Graph of light intensity I in lux against distance d in metres. Seven points fall steeply from 1240 lx at 0.20 m to 77 lx at 0.80 m along a blue curve labelled I = k/d².Graph of light intensity I in lux against distance d in metres. Seven points fall steeply from 1240 lx at 0.20 m to 77 lx at 0.80 m along a blue curve labelled I = k/d².
Sample data. The curve looks like an inverse square, but the shape alone cannot distinguish 1/d² from 1/d or an exponential decay.

The curve has the expected shape, but a curve that falls steeply and levels off fits several models. If the lamp behaves as a point source, I=k/d2I=k/d2, so plotting II against 1/d21/d2 should give a straight line through the origin.

Graph of light intensity I in lux against 1/d² in m⁻² from 0 to 28. Seven points lie on a straight blue line through the origin with gradient 49.8 lx m².Graph of light intensity I in lux against 1/d² in m⁻² from 0 to 28. Seven points lie on a straight blue line through the origin with gradient 49.8 lx m².
Sample data, linearised. Plotting I against 1/d² gives a straight line through the origin, which tests the inverse-square law directly; the gradient is the constant k.

The points lie on a straight line through the origin (the intercept, 1.8 lx, is small compared with the readings), so the data support the inverse-square law over this range, and the gradient gives k=49.8 lx m2k=49.8 lx m2.

Log–log graphs for an unknown power

If theory gives y=kxny=kxn but the power nn is unknown (or is what the investigation is testing), taking logarithms of both sides gives

ln⁡y=nln⁡x+ln⁡klny=nlnx+lnk

so a graph of ln⁡ylny against ln⁡xlnx is a straight line with gradient nn and intercept ln⁡klnk. For the light data the gradient is −2.00, confirming the power. A log–log graph is the best first test when the form of a power law is in doubt, because a straight line on it shows that a power law holds at all, and the gradient gives the power.

Graph of ln of intensity against ln of distance. The x-axis runs from −1.8 to 0 and the y-axis from 4 to 7.5. Seven points lie on a straight blue line falling to the right with gradient −2.00.Graph of ln of intensity against ln of distance. The x-axis runs from −1.8 to 0 and the y-axis from 4 to 7.5. Seven points lie on a straight blue line falling to the right with gradient −2.00.
Sample data on a log–log graph. A straight line shows a power law, and its gradient, −2.00, is the power: I ∝ d⁻². This works even when the power is not known in advance.

Common mistake

Taking the logarithm of a quantity with units without dividing by the unit first. The axis is labelled ln(d / m), meaning the logarithm of the number of metres. Writing ln d / m suggests the logarithm has a unit, which it cannot.

Uncertainties on log and transformed axes

When a quantity is transformed, its error bar is transformed too. For a power, the percentage uncertainty is multiplied by the power: if d=0.300±0.002d=0.300±0.002 m (0.7%), then 1/d21/d2 has an uncertainty of 1.3%. For a natural logarithm, the absolute uncertainty is the fractional uncertainty of the original value:

Δ(ln⁡x)≈ΔxxΔ(lnx)≈xΔx​

So a reading of 77±277±2 lx has ln⁡I=4.344±0.026lnI=4.344±0.026. The error bars on a log graph are therefore of similar size for points with the same percentage uncertainty, even when the original values differ greatly.

A fully worked analysis

The worked analysis follows one sample data set from raw readings to a final value with its uncertainty: the resistivity of constantan wire. The data are illustrative, of the kind a student would obtain with the apparatus of a wire on a metre rule connected to a digital ohmmeter.

The data in this analysis are sample data, made up for teaching. They are realistic in size and scatter, but they are not real measurements.

Research question and theory

How does the length of a 0.38 mm diameter constantan wire, from 0.100 m to 0.800 m, affect its resistance, and what is the resistivity of constantan? For a uniform wire, R=ρL/AR=ρL/A, where ρρ is the resistivity. The leads and clip contacts add a constant resistance R0R0​, so the prediction is a straight line R=(ρ/A)L+R0R=(ρ/A)L+R0​ with gradient ρ/Aρ/A.

Raw data

LL / m ± 0.002

Trial 1 RR / Ω ± 0.01

Trial 2 RR / Ω ± 0.01

Trial 3 RR / Ω ± 0.01

0.100

0.70

0.61

0.64

0.200

1.01

1.10

1.12

0.300

1.53

1.58

1.47

0.400

1.85

1.93

1.98

0.500

2.41

2.30

2.39

0.600

2.79

2.87

2.74

0.700

3.17

3.25

3.30

0.800

3.73

3.62

3.65

Sample data. The clip was removed and replaced between trials, so the spread includes the variation in contact resistance. The diameter was measured with a micrometer at five points along the wire: 0.37, 0.38, 0.38, 0.39 and 0.38 mm (zero reading checked as 0.00 mm). With the clips touching, the resistance was 0.20 Ω.

Processing

Mean resistance and uncertainty. For L=0.400L=0.400 m:

Rˉ=1.85+1.93+1.983=1.92 ΩΔR=1.98−1.852=0.065≈0.07 ΩRˉΔR​=31.85+1.93+1.98​=1.92 Ω=21.98−1.85​=0.065≈0.07 Ω​

Half the range is larger than the ohmmeter's resolution (0.01 Ω), so the spread sets the uncertainty. The other lengths are processed the same way.

LL / m ± 0.002

Mean RR / Ω

ΔRΔR / Ω

0.100

0.65

0.05

0.200

1.08

0.06

0.300

1.53

0.06

0.400

1.92

0.07

0.500

2.37

0.06

0.600

2.80

0.07

0.700

3.24

0.07

0.800

3.67

0.06

Diameter. The mean of the five readings is 0.38 mm and half the range is 0.01 mm, so d=0.38±0.01d=0.38±0.01 mm and A=(1.13±0.06)×10−7 m2A=(1.13±0.06)×10−7 m2, as found in the area example.

Graph. The resistance graph plots mean RR against LL with error bars. All eight points lie within their error bars of the best-fit line, so the data support a linear relationship over the whole range. The gradient is m=4.31±0.16 Ω m−1m=4.31±0.16 Ω m−1 (3.7%), and the intercept is 0.22±0.07 Ω0.22±0.07 Ω.

Resistivity. Since m=ρ/Am=ρ/A,

ρ=mA=4.31×1.134×10−7=4.89×10−7 Ω mΔρρ=Δmm+ΔAA=3.7%+5.3%=9.0%Δρ=0.090×4.89×10−7=0.44×10−7 Ω mρρΔρ​Δρ​=mA=4.31×1.134×10−7=4.89×10−7 Ω m=mΔm​+AΔA​=3.7%+5.3%=9.0%=0.090×4.89×10−7=0.44×10−7 Ω m​

So ρ=(4.9±0.4)×10−7 Ω mρ=(4.9±0.4)×10−7 Ω m.

The analysis has answered both parts of the question: resistance increases linearly with length (with a constant offset), and the resistivity has been found with an honest uncertainty. The diameter contributes more than half of the final uncertainty, which the evaluation will discuss. The intercept, 0.22 ± 0.07 Ω, agrees with the 0.20 Ω measured with the clips touching, which supports the explanation that it is the resistance of the leads and contacts.

Exam tip

Using the gradient rather than a single reading is what makes this analysis strong. A resistivity calculated from one length would include the 0.2 Ω lead resistance as if it were part of the wire, giving a value about 50% too high at 0.100 m, where the wire itself contributes only about 0.43 Ω of the 0.65 Ω. The gradient removes any constant offset automatically.

Applying the ideas

Worked example

A student times 10 oscillations of a mass on a spring three times: 7.48 s, 7.62 s and 7.55 s. Determine the period and its uncertainty, and calculate T2T2 with its uncertainty.

Show the solution
10T‾=7.48+7.62+7.553=7.55 sΔ(10T)=7.62−7.482=0.07 s10TΔ(10T)​=37.48+7.62+7.55​=7.55 s=27.62−7.48​=0.07 s​

Dividing by the exact number 10: T=0.755±0.007T=0.755±0.007 s.

T2=0.7552=0.570 s2Δ(T2)T2=2×0.0070.755=1.9%Δ(T2)=0.019×0.570=0.011≈0.01 s2T2T2Δ(T2)​Δ(T2)​=0.7552=0.570 s2=2×0.7550.007​=1.9%=0.019×0.570=0.011≈0.01 s2​

So T2=0.57±0.01 s2T2=0.57±0.01 s2. Here the spread of the repeats (0.07 s) is smaller than a typical reaction-time estimate (0.2 s per reading); a student who argued for the larger value should say so, and the uncertainty would grow accordingly.

Choosing between two estimates of uncertainty, as in that example, is itself part of the analysis. The report states which was used and why.

Worked example

A student predicts that the time tt for a ball to roll down a ramp of length ss from rest is related by s=12at2s=21​at2. State what should be plotted to give a straight line, and how aa is found.

Show the solution

Plot ss (vertical) against t2t2 (horizontal). The theory predicts a straight line through the origin with gradient 12a21​a, so a=2×gradienta=2×gradient, with the same percentage uncertainty as the gradient.

Alternatively t2t2 could be plotted against ss, giving gradient 2/a2/a. Either is acceptable; putting the measured quantity with the larger uncertainty on the vertical axis makes the error bars easier to draw.

Both forms test the same prediction. Choosing which quantity to put on each axis is a design decision that the report can justify in a sentence.

Worked example

The gradient of a student's graph of T2T2 (in s2s2) against mass mm (in kg) for a mass on a spring is 1.62±0.05 s2 kg−11.62±0.05 s2 kg−1, and the intercept is 0.031±0.012 s20.031±0.012 s2. Determine the spring constant with its uncertainty, and suggest what the intercept shows.

Show the solution

Spring constant. From T2=(4π2/k)mT2=(4π2/k)m, the gradient is 4π2/k4π2/k:

k=4π21.62=24.4 N m−1Δkk=0.051.62=3.1%,Δk=0.8 N m−1kkΔk​​=1.624π2​=24.4 N m−1=1.620.05​=3.1%,Δk=0.8 N m−1​

So k=24.4±0.8 N m−1k=24.4±0.8 N m−1. The units check: kg/s2kg/s2 is the same as N m−1N m−1.

Intercept. The simple theory predicts zero, but the intercept, 0.031±0.012 s20.031±0.012 s2, does not include zero. A positive intercept on T2T2 is what the spring's own mass would produce, because part of the spring moves with the load, adding an effective mass that the plotted mm leaves out. The intercept divided by the gradient estimates that effective mass: 0.031/1.62≈0.0190.031/1.62≈0.019 kg.

Self-check

  • To do:

    I can record raw data in a table with quantities, units, uncertainties and consistent decimal places.

  • To do:

    I can estimate the uncertainty of a reading and of a set of repeated readings.

  • To do:

    I can identify an outlier and justify how it was treated.

  • To do:

    I can propagate uncertainties through sums, differences, products, quotients and powers.

  • To do:

    I can show a sample calculation and present processed data in a table.

  • To do:

    I can draw a graph with labelled axes, error bars and a line of best fit.

  • To do:

    I can find a gradient and intercept with uncertainties from maximum and minimum lines.

  • To do:

    I can linearise a predicted relationship, including with a log–log graph for an unknown power.

  • To do:

    I can carry an analysis through from raw data to a final value with its uncertainty.

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