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  3. Paper 1B: data-based questions

Paper 1B: data-based questions

How to answer Paper 1B questions on experimental work: uncertainties and their propagation, graphs, percentage error, random and systematic errors, evaluation and improvements, with a complete worked question.

  • IB Chemistry
  • Exam skills
  • SL and HL

20 min readLast reviewed 14 Oct 2026

Paper 1B is the second booklet of Paper 1. It contains a few questions, each built around one experiment, often an investigation of a real-world sample: iron in a food, a vitamin in a vegetable, the rate of a reaction at several temperatures. A short stem describes the purpose and the method, then a table of data or a graph follows, and the parts step through the skills of practical chemistry. Each part is small, usually 1 or 2 marks.

The questions test the same skills as the internal assessment: reading data with their uncertainties, processing them, drawing and reading graphs, and judging how far a result can be trusted. The chemistry needed is usually simple; what earns the marks is precision about measurement, error and method.

Key points

  • Every measurement has an uncertainty; a difference of two readings (a titre, a temperature change) carries the uncertainty of both.

  • Absolute uncertainties add for sums and differences; percentage uncertainties add for products and quotients.

  • Percentage error compares a result with an accepted value; if it is larger than the percentage uncertainty, a systematic error is present.

  • Random errors scatter results and are reduced by repeats; systematic errors shift every result the same way and are not.

  • A systematic error needs a direction: does it make the result too high or too low, and why?

  • Weaknesses and improvements must be specific to the method; "human error" and "better equipment" score nothing.

Reading the experiment and its data

Read the stem twice: once for the chemistry (the reaction, the equation, what is measured) and once for the method (the apparatus, the amounts, what is kept constant). Then look at the table headings. In IB data tables, each column heading gives the quantity, its unit and its uncertainty, such as "Volume of NaOH added / cm³ ± 0.05" or "Temperature / °C ± 0.1". The values in the column are recorded to the precision of the instrument, so every value in a column has the same number of decimal places.

Most experiments change one independent variable, measure one dependent variable and keep every other factor that could affect the result constant as control variables. Questions often ask for these by name, and the commonest lost mark is naming a processed quantity as the dependent variable. In a titration the measured dependent variable is the titre, not the concentration calculated from it; in a rate experiment it is the time taken, not the rate.

Worked example

A student investigates how the concentration of sodium thiosulfate affects the rate of its reaction with hydrochloric acid, timing how long a cross drawn under the flask takes to disappear from view as sulfur forms. Identify the independent variable, the dependent variable and two control variables. [2]

Show the markscheme
  • independent: concentration of sodium thiosulfate AND dependent: time for the cross to disappear ✓

  • Any two control variables: volume and concentration of hydrochloric acid / temperature / total volume or depth of solution / the same cross and the same lighting / the same size and shape of flask ✓

Do not accept "rate" as the dependent variable: the rate is calculated from the time measured. Do not accept "amount of acid" without saying whether volume or concentration is meant.

Exam tip

Control variables must be specific to the method. "Temperature" and "volume of acid" earn marks; "the same conditions" or "a fair test" do not. Where a question asks how a variable is controlled, give the method as well: "temperature, by using a water bath at 25 °C".

Uncertainty in a measurement

Definition

The absolute uncertainty of a measurement is the range within which the true value is expected to lie, written ±± after the value in the same unit: 24.35±0.05 cm324.35±0.05 cm3.

For a digital instrument such as a balance or a temperature probe, the uncertainty is usually taken as the smallest division of the display: ±0.01 g±0.01 g for a balance reading to two decimal places. For an analogue scale such as a burette or a thermometer, it is usually half the smallest division: a burette marked every 0.1 cm30.1 cm3 is read to ±0.05 cm3±0.05 cm3. Volumetric glassware carries a manufacturer's tolerance printed on it, such as 25.00±0.06 cm325.00±0.06 cm3 for a pipette, and questions give this value when it is needed.

Many quantities are the difference of two readings: a titre (final minus initial burette reading), a temperature change (final minus initial temperature) or a mass lost (before minus after). Each reading has its own uncertainty, so the difference carries both: a titre found from two burette readings of ±0.05 cm3±0.05 cm3 each is uncertain by ±0.10 cm3±0.10 cm3.

Definition

The percentage uncertainty is the absolute uncertainty divided by the measured value, multiplied by 100. It shows how significant the uncertainty is compared with the size of the measurement.

percentage uncertainty=absolute uncertaintymeasured value×100percentage uncertainty=measured valueabsolute uncertainty​×100

Worked example

A titre is recorded as 12.40 cm312.40 cm3. The burette has an uncertainty of ±0.05 cm3±0.05 cm3 per reading. Calculate the percentage uncertainty in the titre, and suggest how the method could be changed to reduce it. [2]

Show the markscheme
  • 0.1012.40×100=0.8112.400.10​×100=0.81 «%» ✓

  • use a more dilute titrant/a larger volume of the solution in the flask, so that the titre is larger ✓

Award [1 max] for M1 if ±0.05±0.05 is used instead of ±0.10±0.10 (0.40 %). Do not accept "use a more precise burette" without saying how.

Common mistake

Using the uncertainty of one reading for a difference of two readings. A titre, a temperature rise and a mass lost each come from two readings, so the absolute uncertainty is doubled: ±0.10 cm3±0.10 cm3 for a titre from a burette read to ±0.05 cm3±0.05 cm3.

Tip

A larger measurement with the same instrument has a smaller percentage uncertainty. This is the reason behind many improvements: use a larger mass of solid, a larger temperature change (more concentrated reagents), or a larger titre (a more dilute titrant).

Propagating uncertainties

When measured values are combined in a calculation, their uncertainties combine too, a process called propagation of uncertainties. The rules are printed in the data booklet:

  • Adding or subtracting: add the absolute uncertainties. If y=a±by=a±b, then Δy=Δa+ΔbΔy=Δa+Δb.

  • Multiplying or dividing: add the fractional or percentage uncertainties. If y=abcy=cab​, then Δyy=Δaa+Δbb+ΔccyΔy​=aΔa​+bΔb​+cΔc​.

  • Raising to a power (HL): multiply the fractional uncertainty by the power. If y=any=an, then Δyy=∣n∣ΔaayΔy​=∣n∣aΔa​.

Pure numbers, such as the 1000 that converts cm3cm3 to dm3dm3, the coefficients in an equation and constants from the data booklet, add no uncertainty. The final absolute uncertainty is usually given to one significant figure, and the value is then rounded to the same decimal place as its uncertainty.

Worked example

In a titration, 25.00±0.06 cm325.00±0.06 cm3 of sodium hydroxide solution is neutralized by 24.50±0.10 cm324.50±0.10 cm3 of 0.100±0.001 mol dm−30.100±0.001 mol dm−3 hydrochloric acid. Calculate the concentration of the sodium hydroxide and its absolute uncertainty. [3]

Show the markscheme

Concentration. The reaction is 1 : 1, so n(NaOH)=n(HCl)n(NaOH)=n(HCl):

[NaOH]=0.100×24.5025.00=0.0980 mol dm−3[NaOH]=25.000.100×24.50​=0.0980 mol dm−3

Percentage uncertainties. The calculation multiplies and divides, so the percentage uncertainties add:

0.0010.100×100=1.0 %0.1024.50×100=0.41 %0.0625.00×100=0.24 %total=1.65 %≈1.7 %0.1000.001​×10024.500.10​×10025.000.06​×100total​=1.0 %=0.41 %=0.24 %=1.65 %≈1.7 %​

Absolute uncertainty. 0.0165×0.0980=0.0016 mol dm−30.0165×0.0980=0.0016 mol dm−3, which is 0.0020.002 to one significant figure. The result is 0.098±0.002 mol dm−30.098±0.002 mol dm−3.

  • [NaOH]=0.0980[NaOH]=0.0980 «mol dm⁻³» ✓

  • percentage uncertainties added: 1.7 «%» ✓

  • ±0.002±0.002 «mol dm⁻³» ✓

Common mistake

Adding absolute uncertainties when quantities are multiplied or divided. Absolute uncertainties have the units of their quantities, so adding ±0.10 cm3±0.10 cm3 to ±0.001 mol dm−3±0.001 mol dm−3 has no meaning. Convert each to a percentage first, then add.

Graphs in data questions

Most Paper 1B questions include a graph, either given or to be completed. Three graph skills appear again and again in chemistry: extrapolating a line back to a moment when no reading could be taken, drawing a tangent to find a rate, and reading a concentration from a calibration line.

Extrapolating a temperature–time graph

In solution calorimetry, the reacting mixture loses heat to the surroundings while the reaction is still happening, so the highest temperature recorded is lower than the temperature that would have been reached with no heat loss. To correct for this, the temperature is recorded for a few minutes before mixing and for several minutes after the maximum. The cooling line is then extrapolated back to the time of mixing, and the temperature change is read at that time. This extrapolation assumes that heat was lost at the same rate during the reaction as during the cooling.

Temperature against time for a displacement reaction in a polystyrene cup. The temperature is steady at 21.0 °C for 3 minutes, rises steeply after zinc is added, peaks at 30.4 °C at 5 minutes and then falls slowly. The cooling line is extended back to 3.0 minutes, where it reaches 30.8 °C.Temperature against time for a displacement reaction in a polystyrene cup. The temperature is steady at 21.0 °C for 3 minutes, rises steeply after zinc is added, peaks at 30.4 °C at 5 minutes and then falls slowly. The cooling line is extended back to 3.0 minutes, where it reaches 30.8 °C.
Temperature–time data for zinc powder added to copper(II) sulfate solution. The blue dashed line extends the cooling line back to the time of mixing; the vertical span between it and the starting line is the temperature rise that would have been reached with no heat loss.

Worked example

Zinc powder (in excess) is added at 3.0 min to 50.0 cm350.0 cm3 of 0.200 mol dm−30.200 mol dm−3 copper(II) sulfate solution in a polystyrene cup, and the temperature is recorded as in the temperature–time graph. (a) Determine the temperature change, ΔTΔT, by extrapolation. [1] (b) Calculate the enthalpy change, in kJ mol−1kJ mol−1, for Zn(s)+CuSOX4(aq)→ZnSOX4(aq)+Cu(s)Zn(s)+CuSOX4​(aq)​ZnSOX4​(aq)+Cu(s). State one assumption you make. [3]

Show the markscheme

(a)

  • ΔT=30.8−21.0=9.8ΔT=30.8−21.0=9.8 «K or °C» ✓

Accept values from 9.6 to 10.0. Award [0] for 9.4, the difference between the highest reading and the starting temperature.

(b)

  • Q=50.0×4.18×9.8=2048Q=50.0×4.18×9.8=2048 «J» =2.05=2.05 «kJ» ✓

  • n(CuSOX4)=0.0500×0.200=0.0100n(CuSOX4​)=0.0500×0.200=0.0100 «mol» ✓

  • ΔH=−2.050.0100=−205ΔH=−0.01002.05​=−205 «kJ mol⁻¹» ✓

Assumption, any one of: the density of the solution is 1.00 g cm−31.00 g cm−3 / its specific heat capacity equals that of water / the heat capacity of the cup is negligible / all the heat released is absorbed by the solution. Award [2 max] for +205+205. Accept ECF from (a).

Common mistake

Using the mass of the solid (the zinc) or of the solute in Q=mcΔTQ=mcΔT. The mass is that of the solution that is heated, here 50.0 g50.0 g from 50.0 cm350.0 cm3, and the limiting reactant sets the amount in moles. The negative sign for an exothermic reaction also carries a mark.

Tangents and initial rates

On a graph of the amount of product (or of reactant) against time, the rate at any instant is the gradient of the tangent to the curve at that time. The initial rate is the gradient of the tangent at t=0t=0. Draw the tangent with a ruler so that it touches the curve at that point without cutting it, extend it as far as possible, and calculate its gradient from two points on the tangent that are far apart. The unit of the rate is the unit of the vertical axis divided by the unit of the horizontal axis.

Volume of oxygen collected against time, rising steeply at first and levelling off near 60 cm³ after about 160 s. A straight blue tangent is drawn at the origin and passes through the point (40 s, 60 cm³).Volume of oxygen collected against time, rising steeply at first and levelling off near 60 cm³ after about 160 s. A straight blue tangent is drawn at the origin and passes through the point (40 s, 60 cm³).
Volume of oxygen collected in a gas syringe during the catalysed decomposition of hydrogen peroxide. The tangent at t = 0 (blue) gives the initial rate; the dashed guides mark a point on it read from the grid.

Worked example

Hydrogen peroxide decomposes in the presence of a manganese(IV) oxide catalyst, and the oxygen is collected in a gas syringe. Determine the initial rate of reaction from the graph, including its units. [2]

Show the markscheme
  • tangent drawn at t=0t=0 AND gradient calculated, for example 60−040−040−060−0​ ✓

  • 1.5 cm3 s−11.5 cm3 s−1 ✓

Accept answers from 1.3 to 1.7 cm3 s−11.7 cm3 s−1. The unit is required for M2.

Tip

Use the largest triangle you can draw. Reading two points that are close together makes the small errors in reading each one a large fraction of the gradient. On the graph, the tangent runs from the origin to (40 s,60 cm3)(40 s,60 cm3), so the readings are easy to take from grid lines.

Calibration lines and R²

In colorimetry, the absorbance of a coloured solution is measured at a wavelength that it absorbs strongly, which is the colour complementary to the one it appears (the colour wheel in the data booklet shows the pairs). A blue solution absorbs orange light, so an orange filter, or a wavelength of about 600–640 nm, gives the most sensitive readings. The instrument is first zeroed with a blank: a cuvette of the solvent with everything except the coloured substance.

A set of standard solutions of known concentration is measured, and absorbance is plotted against concentration to give a calibration curve. The concentration of an unknown is then found by reading across from its absorbance, which is interpolation, or by substituting into the equation of the best-fit line. The calculation from the equation uses all the standards and avoids the error of reading a graph by eye.

Calibration graph of absorbance against concentration of a blue dye from 0 to 5 mg dm⁻³: six standards lie close to a straight line with equation A = 0.1616c + 0.0034 and R² = 0.9997. A sample with absorbance 0.420 is read across to a concentration of 2.58 mg dm⁻³.Calibration graph of absorbance against concentration of a blue dye from 0 to 5 mg dm⁻³: six standards lie close to a straight line with equation A = 0.1616c + 0.0034 and R² = 0.9997. A sample with absorbance 0.420 is read across to a concentration of 2.58 mg dm⁻³.
Calibration graph for a blue food dye measured with an orange filter. The dashed guides read the concentration of a sample from its absorbance; the equation of the line gives the same value by calculation.

Definition

The coefficient of determination, R2R2, measures how closely data points fit a trend line. A value of 1 means every point lies exactly on the line; the further below 1, the more the points scatter about it.

Worked example

A sports drink is diluted by a factor of 10, and the absorbance of the diluted drink is 0.420. Using the equation of the calibration line, determine the concentration of the dye in the undiluted drink. [2]

Show the markscheme
  • c=0.420−0.00340.1616=2.58c=0.16160.420−0.0034​=2.58 «mg dm⁻³» ✓

  • 2.58×10=25.82.58×10=25.8 «mg dm⁻³» ✓

Accept a value read from the graph between 2.5 and 2.7 for M1. Accept ECF for M2.

Exam tip

Three points about calibration lines are tested repeatedly. An R2R2 close to 1 shows that the points lie close to a straight line, so the line is reliable for interpolation; it does not show that the method is accurate. A reading outside the range of the standards needs an extrapolation that may not be valid, because the relationship may not stay linear, so the sample should be diluted and measured again. The blank removes the absorbance of the solvent and the cuvette.

Percentage error and percentage uncertainty

Definition

The percentage error compares an experimental result with an accepted (literature) value: ∣experimental value−accepted value∣accepted value×100accepted value∣experimental value−accepted value∣​×100. It measures the accuracy of the result.

The two percentages answer different questions. Percentage uncertainty comes from the precision of the apparatus and says how much the result could vary from random effects alone. Percentage error says how far the result actually is from the accepted value. Comparing them is one of the most useful judgements in a data question: if the percentage error is larger than the total percentage uncertainty, random uncertainty cannot explain the difference, and a systematic error must be present.

Worked example

The enthalpy change for Zn(s)+CuX2+(aq)→ZnX2+(aq)+Cu(s)Zn(s)+CuX2+(aq)​ZnX2+(aq)+Cu(s) calculated from standard enthalpies of formation is −219 kJ mol−1−219 kJ mol−1. The student's value was −205 kJ mol−1−205 kJ mol−1. The thermometer reads to ±0.1 ∘C±0.1 ∘C and the measuring cylinder to ±0.5 cm3±0.5 cm3. (a) Calculate the percentage error. [1] (b) Comment on whether random uncertainty accounts for the difference. [2]

Show the markscheme

(a)

  • 219−205219×100=6.4219219−205​×100=6.4 «%» ✓

(b)

  • percentage uncertainty: ΔTΔT: 0.29.8×100=2.0 %9.80.2​×100=2.0 %; volume: 0.550.0×100=1.0 %50.00.5​×100=1.0 %; total about 3 %3 % ✓

  • the percentage error is larger than the percentage uncertainty, so random errors do not account for it/a systematic error «such as heat loss» is present ✓

Common mistake

Using "percentage error" and "percentage uncertainty" as if they meant the same thing. The uncertainty is calculated from the apparatus before any comparison is made; the error needs an accepted value. Examiners report this confusion in almost every set of data questions.

Random errors, systematic errors and their direction

A random error varies unpredictably from one measurement to the next: judging when a colour changes, reading a scale between divisions, small fluctuations in temperature. Random errors scatter the results on both sides of the true value and limit the precision of the results. Repeating the measurement and taking a mean reduces their effect.

A systematic error shifts every result in the same direction by a similar amount: heat lost to the surroundings in every calorimetry run, a standard solution whose concentration is lower than its label, a balance that reads 0.02 g0.02 g too high. Systematic errors limit the accuracy of the results, and repeating the measurement does not reduce them, because every repeat is wrong in the same way.

Definition

Accuracy is how close a result is to the true or accepted value. Precision is how close repeated results are to one another. A set of results can be precise but inaccurate, when a systematic error shifts them all together.

Questions on systematic error almost always ask for a direction: will the error make the final result too high or too low? Work through the chain from the measured quantity to the result one step at a time.

Source of systematic error

Effect on the measurement

Effect on the result

Heat lost to the surroundings in solution calorimetry

Temperature rise too small

ΔHΔH less negative (its magnitude too small)

Fuel evaporating from the wick of a spirit burner

Mass of fuel burned overestimated

Magnitude of ΔHcΔHc​ too small

Hydrated salt not heated to constant mass

Mass of water lost too small

Number of waters of crystallization too low

Carbon dioxide collected over water partly dissolves

Volume of gas too small

Amount of gas, and the rate, too low

Sodium hydroxide titrant absorbs carbon dioxide from the air, so its concentration is lower than stated

Titre too large

Calculated concentration of the acid too high

Other reducing agents in a sample also react with the oxidizing titrant

Titre too large

Amount of the analyte overestimated

Exam tip

Give the direction and the reason together: "heat was lost to the surroundings, so the temperature rise was too small and the calculated enthalpy change is less exothermic than the true value". A bare "heat loss" usually earns at most one of two marks.

Tip

Some systematic errors cancel. A balance that reads 0.02 g too high adds the same amount to both weighings, so a mass found by difference is unaffected. Reading a burette consistently from above the meniscus shifts both readings equally, so the titre is unaffected. Checking whether an error cancels is a quick way to decide whether it matters.

Repeats, outliers and significant differences

Repeated trials show how precise a method is. In a titration, trials are repeated until two or more concordant titres agree within ±0.10 cm3±0.10 cm3, and only those are averaged; the rough trial is never included. In other experiments, an outlier (an anomalous result) is a value that lies well outside the pattern of the others. It may be excluded from the mean, but only with a reason: the value is clearly inconsistent with the repeats, and ideally a cause specific to the method can be suggested.

Two results differ significantly only if the difference between them is larger than their combined uncertainty. If the ranges value±uncertaintyvalue±uncertainty overlap, the data do not show a real difference. This test answers questions such as "Comment on whether the iron content changed between day 4 and day 5" or "Does the temperature affect the result?"

Common mistake

Excluding a result only because it does not fit the expected answer, or averaging every trial including the rough titration. A result is excluded because it is inconsistent with the repeats, and the exclusion is stated.

Evaluating and improving a method

Evaluation questions ask for weaknesses in the method, their effect on the result, and realistic improvements. Each improvement must address a named weakness, use apparatus available in a school laboratory, and say what it changes. A generic answer that could be written about any experiment earns nothing.

Weakness

Why it matters

Realistic improvement

Heat lost from an open polystyrene cup

Temperature rise too small, so the enthalpy change is underestimated

Fit a lid and add insulation; extrapolate the cooling line back to the time of mixing

End point judged by eye (a cross disappearing, a colour change)

The moment chosen varies between trials: a random error

Use a light sensor or colorimeter and record the time when the transmitted light falls to a fixed value

Small titre, under about 10 cm³

Large percentage uncertainty in the titre

Use a more dilute titrant or a larger volume of the analyte

Gas escapes before the bung is inserted

Volume of gas collected is too small

Keep one reactant in a small tube inside the sealed flask and tip it over to start the reaction

Only three values of the independent variable

Too few points to establish a trend

Use at least five values over a wider range

A single trial at each value

Random errors are not reduced

Repeat each measurement at least three times and use the mean

Calculations from experimental data rest on assumptions, and questions often ask for one. In calorimetry: the solution has the density (1.00 g cm−31.00 g cm−3) and specific heat capacity (4.18 J g−1 K−14.18 J g−1 K−1) of water, no heat is lost, and the cup absorbs no heat. In gas experiments: the gas behaves ideally and none dissolves or escapes. In titrations: the reaction goes to completion and nothing else in the sample reacts with the titrant.

Questions on safety, ethical and environmental issues need a specific hazard and a specific precaution: hydrochloric acid is corrosive, so eye protection is worn; sulfur dioxide is toxic, so the experiment is done in a fume cupboard; copper(II) sulfate solution is harmful to aquatic life, so it is collected for disposal rather than poured down the sink. "Be careful", "it is dangerous" and "wear a lab coat" alone score nothing.

A complete Paper 1B question

The worked question follows one experiment through the skills of the earlier sections. A student investigates the effect of temperature on the rate of the reaction between sodium thiosulfate and hydrochloric acid:

NaX2SX2OX3(aq)+2 HCl(aq)→2 NaCl(aq)+S(s)+SOX2(g)+HX2O(l)NaX2​SX2​OX3​(aq)+2HCl(aq)​2NaCl(aq)+S(s)+SOX2​(g)+HX2​O(l)

Equal volumes of the two solutions are warmed separately in a water bath to the chosen temperature, mixed in a conical flask standing on a paper marked with a cross, and timed until the precipitate of sulfur hides the cross. The results are recorded in a table.

Temperature / °C ± 0.5

Time, trial 1 / s ± 1

Time, trial 2 / s ± 1

Time, trial 3 / s ± 1

Mean time / s

20.0

92

95

90

92

30.0

51

49

53

51

40.0

29

41

28

50.0

17

18

16

17

Worked example

(a) Identify the anomalous result and suggest one reason for it that is specific to this method. [2]

(b) Calculate the mean time at 40.0 ∘C40.0 ∘C and the relative rate, 1tt1​, in s−1s−1. [2]

(c) Calculate the percentage uncertainty in the time of the first trial at 50.0 ∘C50.0 ∘C. [1]

(d) Suggest why the true uncertainty of each time is larger than ±1 s±1 s. [1]

(e) Explain, using collision theory, why the time decreases as the temperature increases. [2]

(f) Suggest one modification that would reduce the random error in judging when the cross disappears. [1]

(g) State one safety precaution specific to this experiment. [1]

Show the markscheme

(a)

  • 41 s at 40.0 °C ✓

  • Any one: the mixture cooled before or during timing / the solutions were not left long enough in the water bath to reach 40 °C / the end point was judged differently ✓

Do not accept "human error" or "timing mistake" without a specific cause.

(b)

  • mean of 29 and 28 = 28.5 «s» ✓

  • 128.5=0.0351 s−128.51​=0.0351 s−1 ✓

Award [1 max] for a mean of 32.7 s that includes the anomalous result. Accept ECF for the rate.

(c)

  • 117×100=5.9171​×100=5.9 «%» ✓

(d)

  • the moment at which the cross disappears is judged by eye and varies between trials/depends on the observer and the lighting ✓

(e)

  • particles have a greater average kinetic energy, so a greater proportion of collisions have energy ≥Ea≥Ea​ ✓

  • more frequent successful collisions/more successful collisions per unit time ✓

Do not accept "more collisions" alone.

(f)

  • use a light sensor/colorimeter to record the time at which the light transmitted falls to a fixed value ✓

Accept "the same person judges every trial, with the same cross and lighting". Do not accept "repeat more times": repeats reduce the effect of random error on the mean, but not the error in judging each end point.

(g)

  • sulfur dioxide is toxic/an irritant, so carry out the experiment in a fume cupboard/well-ventilated room ✓

Accept "wear eye protection because hydrochloric acid is corrosive/an irritant".

Exam tip

Read every part before starting. Later parts often explain earlier ones: in the worked question, the request in (d) for why the uncertainty is larger than ±1 s points to the judgement of the end point, which is also a valid cause for (a) and the key to (f).

Self-check

  • To do:

    I can identify the independent, dependent and control variables of an experiment, naming the measured dependent variable.

  • To do:

    I can state the uncertainty of a reading and double it for a difference of two readings.

  • To do:

    I can calculate percentage uncertainties and propagate them through sums, differences, products and quotients.

  • To do:

    I can extrapolate a temperature–time graph to find the temperature change at the time of mixing.

  • To do:

    I can draw a tangent and calculate an initial rate with its units.

  • To do:

    I can use a calibration line and its equation, and explain what R², the blank and the range of the standards mean.

  • To do:

    I can calculate a percentage error and compare it with the percentage uncertainty to decide whether a systematic error is present.

  • To do:

    I can distinguish random from systematic errors and give the direction in which a systematic error shifts a result.

  • To do:

    I can exclude an outlier with a reason and judge whether a difference between results is significant.

  • To do:

    I can give specific weaknesses, realistic improvements, assumptions and safety precautions for a method.

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More IB Chemistry notes

  • Paper 1A: multiple choiceThe page before this.
  • Paper 2: short and extended responsesThe next page.
  • Chemistry assessmentEach Chemistry paper, the internal assessment and grade boundaries.
  • IB ChemistryThe Chemistry syllabus, how it is assessed and every notes page.

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