1.15 Proof by induction, contradiction and counterexample questions for IB Maths AA

37 questions on Proof by induction, contradiction and counterexample, written by Augment in the style of IB exam papers. Six of them are below in full, to answer on paper.

  • IB Mathematics: Analysis and Approaches
  • Part of 1 Number and algebra
  • HL only

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Written by Augment in the style of IB exams, not past papers. Answer them on paper, then check each one against its markscheme with a free account.

Question 1 · AA-00182Paper 1 · 16 marks

Let Sn=∑r=1narctan⁡(2r2), for n∈Z+.

  1. (a)

    Show that arctan⁡p−arctan⁡q=arctan⁡(p−q1+pq), for p,q≥0.

    3 marks

  2. (b)

    Hence show that arctan⁡(n+2)−arctan⁡n=arctan⁡(2(n+1)2), for n≥0.

    2 marks

  3. (c)

    Show that S2=π2.

    2 marks

  4. (d)

    Prove by mathematical induction that Sn=arctan⁡n+arctan⁡(n+1)−π4, for n∈Z+.

    7 marks

  5. (e)

    Find lim⁡n→∞Sn.

    2 marks

Question 2 · AA-00997Paper 2 · 7 marks

Consider the inequality 2n>n3, where n∈Z+.

  1. (a)

    Use your GDC to find the values of n, where 1≤n≤12, for which the inequality is true.

    2 marks

  2. (b)

    Prove by mathematical induction that 2n>n3 for all integers n≥10.

    5 marks

Question 3 · AA-00186Paper 3 · 29 marks

This question asks you to investigate polynomials that express cos⁡nθ in terms of cos⁡θ.

For n∈N, the polynomial Tn(x) is defined so that Tn(cos⁡θ)=cos⁡nθ for all θ∈R. For example, T0(x)=1 and T1(x)=x.

  1. (a)

    Use a double angle identity to show that T2(x)=2x2−1.

    1 mark

  2. (b)

    By expanding cos⁡((n+1)θ) and cos⁡((n−1)θ), show that cos⁡((n+1)θ)+cos⁡((n−1)θ)≡2cos⁡θcos⁡nθ.

    3 marks

  3. (c)

    Hence show that Tn+1(x)=2xTn(x)−Tn−1(x), for n∈Z+.

    2 marks

  4. (d)

    Hence find T3(x) and T4(x).

    3 marks

  5. (e)

    Use your GDC to sketch the graph of y=T4(x) for −1≤x≤1, and write down the range of T4 on this interval.

    2 marks

  6. (f)(i)

    Write down the leading coefficient of Tn(x) for n=1,2,3,4, and hence suggest an expression for the leading coefficient of Tn(x), for n∈Z+.

    1 mark

  7. (f)(ii)

    Prove by mathematical induction that, for n∈Z+, Tn(x) is a polynomial of degree n with leading coefficient 2n−1.

    5 marks

  8. (g)

    Show that the n roots of Tn(x)=0 are x=cos⁡((2k−1)π2n), for k=1,2,…,n.

    4 marks

  9. (h)

    Hence find the exact value of cos⁡π8.

    4 marks

  10. (i)

    By considering the product of the roots of T4(x)=0, find the exact value of cos⁡π8cos⁡3π8.

    4 marks

Question 4 · AA-00206Paper 1 · 8 marks

Consider the vectors a=(1k2) and b=(k44), where k∈R.

  1. (a)

    Find the value of k for which a and b are parallel.

    4 marks

  2. (b)

    For this value of k, write down the value of ∣b∣∣a∣.

    1 mark

  3. (c)

    Let u and v be any two non-zero vectors that are not parallel. Prove by contradiction that u+v and u−v are not parallel.

    3 marks

Question 5 · AA-00998Paper 2 · 10 marks

Let a∈R, where a>0.

  1. (a)

    Prove by mathematical induction that

    (1+a)n≥1+na+n(n−1)2a2,for all n∈Z+.

    7 marks

  2. (b)

    An investment grows by 3% each year, so after 40 years its value has been multiplied by 1.0340.

    Use part (a) to find a lower bound for 1.0340, and find the percentage error when this lower bound is used as an estimate of 1.0340.

    3 marks

Question 6 · AA-00234Paper 3 · 27 marks

This question asks you to investigate an inequality that connects the scalar product of two vectors with their magnitudes, and to use it to solve optimisation problems.

Throughout the question, a and b are non-zero vectors in three dimensions.

  1. (a)

    Using the result a⋅b=∣a∣∣b∣cos⁡θ, where θ is the angle between a and b, show that ∣a⋅b∣≤∣a∣∣b∣, and state the condition on a and b for which equality holds.

    3 marks

  2. (b)(i)

    Let a=(236) and b=(xyz), where x2+y2+z2=1.

    Show that 2x+3y+6z≤7.

    2 marks

  3. (b)(ii)

    Find the values of x, y and z for which 2x+3y+6z=7.

    3 marks

  4. (c)

    The proof in part (a) assumes that the angle θ exists, which itself relies on a⋅b∣a∣∣b∣ lying between −1 and 1. In the rest of the question, you will prove the inequality without using angles.

    Let f(t)=∣a+tb∣2, where t∈R.

    Show that f(t)=∣b∣2t2+2(a⋅b)t+∣a∣2.

    3 marks

  5. (d)

    Explain why f(t)≥0 for all t∈R, and hence show that (a⋅b)2≤∣a∣2∣b∣2.

    4 marks

  6. (e)

    Show that if (a⋅b)2=∣a∣2∣b∣2, then a and b are parallel.

    3 marks

  7. (f)

    Use the result of part (d) to prove that ∣a+b∣≤∣a∣+∣b∣.

    3 marks

  8. (g)

    The real numbers x, y and z satisfy x+2y−2z=12.

    By choosing suitable vectors a and b, find the minimum value of x2+y2+z2 and the values of x, y and z for which it occurs.

    4 marks

  9. (h)

    Show that (p+q+1)2≤3(p2+q2+1) for all p,q∈R.

    2 marks

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The notes on 1.15 Proof by induction, contradiction and counterexample

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