Augment Education
    • Question bank
    • Quick fire
    • Worksheets
    • Flashcards
    • Notes
    • Try a quick-fire round
    • All features
    • Business
    • Digital Society
    • Economics
    • Geography
    • Global Politics
    • History
    • Philosophy
    • Psychology
    • Anthropology
    • World Religions
    • Biology
    • Chemistry
    • Physics
    • Computer Science
    • Design Technology
    • ESS
    • SEHS
    • Language and literature
    • Language acquisition
    • Maths AA
    • Maths AI
    • Dance
    • Film
    • Music
    • Theatre
    • Visual Arts
    • Grade calculator
    • Grade boundaries
    • Subject checker
    • Focus timer
    • Exam countdown
    • All free tools
    • IB guide
    • All subjects
  • Blog

Search

Search subjects, the syllabus, glossary terms, the booklets, the IB guide, help and the blog

Log inStart free
augment

Augment Education

IB Diploma revision built around the syllabus.

contact@augment-education.com

Product

  • Features
  • Question bank
  • Quick fire
  • Worksheets
  • Flashcards
  • Notes
  • Subjects
  • What's new

Learn

  • IB guide
  • Booklets, explained
  • Glossary
  • Blog
  • Free tools
  • Grade calculator
  • Subject checker

Company

  • About
  • Help
  • For parents
  • For teachers
  • Comparisons

Subjects

  • English A Lit
  • English A Lang & Lit
  • Chinese A Lit
  • Chinese A Lang & Lit
  • Spanish A Lit
  • Spanish A Lang & Lit
  • English Lit & Perf
  • Spanish Lit & Perf
  • English B
  • Mandarin B
  • Spanish B
  • English ab initio
  • Mandarin ab initio
  • Spanish ab initio
  • Business
  • Digital Society
  • Economics
  • Geography
  • Global Politics
  • History
  • Philosophy
  • Psychology
  • Anthropology
  • World Religions
  • Biology
  • Chemistry
  • Physics
  • Computer Science
  • Design Technology
  • ESS
  • SEHS
  • Maths AA
  • Maths AI
  • Dance
  • Film
  • Music
  • Theatre
  • Visual Arts

Augment Education is developed independently of the International Baccalaureate Organization and is not endorsed by it. “IB” and “International Baccalaureate” are its trademarks.

© 2026 Augment Education. All rights reserved.

  • Privacy
  • Terms
  1. Subjects
  2. ESS
  3. Criteria D, E and F: data, analysis and evaluation

Criteria D, E and F: data, analysis and evaluation

Process and present data clearly, choose and carry out the right statistical test, explain patterns with bias, reliability, validity and uncertainty, and evaluate weaknesses, improvements and open questions.

  • IB Environmental Systems and Societies
  • Internal assessment
  • SL and HL

30 min readLast reviewed 15 Oct 2026

Criteria D, E and F carry 18 of the 30 marks. They assess what happens after the data are collected: how clearly and correctly the data are processed and presented (D), how well the patterns are interpreted and turned into a supported conclusion (E), and how critically the investigation is evaluated (F). Each is marked in three bands (1–2, 3–4, 5–6). The worked example of reduced mowing continues, with sibling examples for other tests; all data are hypothetical.

Criterion D: treatment of data

Criterion D assesses how effectively you communicate and process the data in ways that are relevant to the research question, using techniques suited to an experimental or social-science investigation.

Band

Communication of raw and processed data

Processing techniques

Accuracy of processing

1–2

Not clear

Lead to findings that do not address the research question

Major errors

3–4

Clear

Lead to findings that do not fully address the research question

Some minor errors

5–6

Clear and detailed

Lead to findings that fully address the research question

Processed correctly

"Clear" has a precise meaning here: the presentation and the method of processing can be understood easily, with appropriate titles, labels, units, decimal places and significant figures. Minor errors that do not change the conclusion do not stop a report reaching the top band. If there is a large amount of raw data (a long survey, data-logger readings), a representative sample can be shown in the report and the rest placed in an appendix.

Raw data tables

Raw data are the measurements as they were recorded, before any calculation. A raw data table has a descriptive title; column and row headings that name the quantity and give its unit in the heading, not in every cell; values recorded to the precision of the instrument, with the same number of decimal places throughout a column; and notes of any qualitative observations (weather, an unusual event, a doubtful identification).

Species (unmown zone, quadrat 1)

Number of individuals, n

n(n − 1)

Trifolium repens (white clover)

8

56

Ranunculus repens (creeping buttercup)

6

30

Plantago lanceolata (ribwort plantain)

5

20

Bellis perennis (daisy)

4

12

Achillea millefolium (yarrow)

3

6

Lotus corniculatus (bird's-foot trefoil)

2

2

Total

N = 28

Σn(n − 1) = 126

The table is one of 20 raw data tables (one per quadrat). In the report, two of them would be shown as examples and the other 18 placed in an appendix, with a summary table of the processed results in the main text.

Worked example

Calculate Simpson's reciprocal index for unmown quadrat 1 from the raw data table, and for mown quadrat 7, which contained 10 Bellis perennis, 6 Trifolium repens, 3 Taraxacum officinale (dandelion) and 1 Plantago major (broadleaf plantain). Comment on the difference. (Hypothetical data.)

Show the solution
D=N(N−1)∑n(n−1)D=∑n(n−1)N(N−1)​

Step 1: unmown quadrat 1. N = 28, so N(N − 1) = 28 × 27 = 756. Σn(n − 1) = 126 (from the table). D = 756 ÷ 126 = 6.0.

Step 2: mown quadrat 7. N = 10 + 6 + 3 + 1 = 20, so N(N − 1) = 20 × 19 = 380. Σn(n − 1) = 90 + 30 + 6 + 0 = 126. D = 380 ÷ 126 = 3.016 = 3.0 (to 1 decimal place).

Step 3: comment. The unmown quadrat has six species with fairly even numbers, while the mown quadrat has four species and is dominated by daisy (half of all individuals). D is higher where species richness and evenness are both higher, so the unmown quadrat is about twice as diverse by this measure. One pair of quadrats proves nothing; the comparison needs all 20.

Processed data and descriptive statistics

Processed data are the results of calculations on the raw data: totals, percentages, rates, indices, means and measures of spread. The processed table for the worked example gives D for every quadrat, then the summary statistics for each zone.

Quadrat

1

2

3

4

5

6

7

8

9

10

Mean

Median

SD

Mown, D

2.7

2.4

3.3

2.9

2.1

2.6

3.0

2.5

2.8

2.2

2.65

2.65

0.37

Unmown, D

6.0

5.1

7.2

5.6

4.4

6.7

5.4

6.3

3.9

5.9

5.65

5.75

1.01

The mean (the sum divided by the number of values) and the median (the middle value when the data are in order) describe the centre of each group. The mode (the most frequent value) is useful mainly for categories, such as the most common answer to a survey question. Measures of spread show how variable the data are, which matters as much as the centre: two groups with different means but huge spread may not really differ.

Definition

Standard deviation: a measure of the spread of values around the mean, calculated as the square root of the variance; about two-thirds of values in normally distributed data lie within one standard deviation of the mean.

Worked example

Calculate the standard deviation of D for the ten mown quadrats: 2.7, 2.4, 3.3, 2.9, 2.1, 2.6, 3.0, 2.5, 2.8, 2.2. (Hypothetical data.)

Show the solution
s=∑(x−xˉ)2n−1s=n−1∑(x−xˉ)2​​

Step 1: the mean. Σx = 26.5, so x̄ = 26.5 ÷ 10 = 2.65.

Step 2: deviations and their squares. x − x̄: 0.05, −0.25, 0.65, 0.25, −0.55, −0.05, 0.35, −0.15, 0.15, −0.45. Squared: 0.0025, 0.0625, 0.4225, 0.0625, 0.3025, 0.0025, 0.1225, 0.0225, 0.0225, 0.2025.

Step 3: sum of squares. Σ(x − x̄)² = 1.225.

Step 4: variance. s² = 1.225 ÷ (10 − 1) = 0.136.

Step 5: standard deviation. s = √0.136 = 0.37 (2 decimal places). The same steps for the unmown quadrats give Σ(x − x̄)² = 9.105, s² = 1.012 and s = 1.01.

Step 6: interpret. The mown quadrats are much less variable (SD 0.37) than the unmown ones (SD 1.01). Unmown grassland is more patchy: some quadrats are rich in species and others are still dominated by a few. This is itself a finding worth explaining in criterion E.

The variance is the square of the standard deviation. The interquartile range (IQR) is the spread of the middle half of the data, from the lower quartile (Q1) to the upper quartile (Q3), and is less affected by extreme values. For the mown quadrats, ordered 2.1, 2.2, 2.4, 2.5, 2.6 | 2.7, 2.8, 2.9, 3.0, 3.3, Q1 is the median of the lower half (2.4) and Q3 the median of the upper half (2.9), so IQR = 0.5. For the unmown quadrats, Q1 = 5.1, Q3 = 6.3 and IQR = 1.2. Spreadsheets use slightly different rules for quartiles, so state which was used.

Box plots of D for hypothetical data. Mown: minimum 2.1, Q1 2.4, median 2.65, Q3 2.9, maximum 3.3. Unmown: minimum 3.9, Q1 5.1, median 5.75, Q3 6.3, maximum 7.2. The boxes and whiskers do not overlap.Box plots of D for hypothetical data. Mown: minimum 2.1, Q1 2.4, median 2.65, Q3 2.9, maximum 3.3. Unmown: minimum 3.9, Q1 5.1, median 5.75, Q3 6.3, maximum 7.2. The boxes and whiskers do not overlap.
Hypothetical data. A box and whisker plot shows median, quartiles and range together. The boxes do not overlap and even the lowest unmown value is above the highest mown value.

A box and whisker plot is the clearest way to compare two or more groups when the data may be skewed. A column chart of means with error bars does the same job for means: each bar shows the mean, and the error bar shows one standard deviation (or another stated measure) above and below it. Where error bars overlap a lot, a difference between means is unlikely to be significant; where they do not overlap at all, it probably is, although only a statistical test can confirm it.

Columns of mean D with error bars of one standard deviation for hypothetical data, five quadrats each: mown weekly 2.3 ± 0.22, mown monthly 3.4 ± 0.29, unmown 5.6 ± 0.52. None of the error bars overlap.Columns of mean D with error bars of one standard deviation for hypothetical data, five quadrats each: mown weekly 2.3 ± 0.22, mown monthly 3.4 ± 0.29, unmown 5.6 ± 0.52. None of the error bars overlap.
Hypothetical data from an extended design with three mowing regimes. The error bars (±1 SD) do not overlap, and the mean D rises as mowing becomes less frequent.

Exam tip

State what the error bars represent in the caption or axis label (±1 SD, ±2 SD, range, or 95% confidence interval). Error bars without a stated meaning cannot be interpreted and count against the clarity that criterion D asks for.

Choosing the right graph

Purpose

Suitable graph

Example

Compare groups (categories)

Column chart of means with error bars; box and whisker plots

Mean D in mown and unmown grassland

Show a relationship between two continuous variables

Scatter graph with a line of best fit

Tree cover against surface temperature

Show change along a gradient or over time

Line graph (point to point) or kite diagram for species along a transect

Species richness against distance from a path

Show parts of a whole

Pie chart or stacked column chart

Percentage of respondents giving each answer

Show direction

Rose diagram

Wind direction at a monitoring site

Every graph has a descriptive title (or caption), axes labelled with the quantity and unit, sensible scales, and the independent variable on the x-axis. One clear graph that answers the research question is worth more than six graphs that repeat the same numbers in different forms.

Statistical tests

Descriptive statistics show what the sample looks like. A statistical test asks whether a difference, correlation or association in the sample is large enough, given the variation and the sample size, that it is unlikely to have arisen by chance. If it is, the result is called statistically significant, and the null hypothesis is rejected.

Definition

Statistical significance: the conclusion that a result (a difference, correlation or association) is unlikely to have arisen by chance alone, usually because the probability of obtaining it if the null hypothesis were true is less than 5% (p < 0.05).

Each test gives a test statistic (t, F, χ², rₛ or r). To decide whether it is significant, the statistic is compared with a critical value from a table, which depends on the chosen significance level (normally p = 0.05) and the degrees of freedom (a number related to the sample size).

If the test statistic is greater than the critical value (for r and rₛ, if its size ignoring the sign is greater), the null hypothesis is rejected. Software gives a p-value instead: the probability of a result at least this extreme if the null hypothesis were true. A p-value below 0.05 means the result is significant at the 5% level.

Decision tree for choosing a test. Differences between two groups: t-test; three or more: ANOVA. Relationships: Spearman's rank for ranked or non-linear data, Pearson's r and R² for linear data. Associations between counts: chi-squared. Checks under each.Decision tree for choosing a test. Differences between two groups: t-test; three or more: ANOVA. Relationships: Spearman's rank for ranked or non-linear data, Pearson's r and R² for linear data. Associations between counts: chi-squared. Checks under each.
The research question decides the test. Differences between groups, relationships between measured variables and associations between categories each have their own tests and their own checks.

Common mistake

Writing that a significant result "proves" the hypothesis, or that a p-value of 0.03 means "a 97% chance the hypothesis is right". A significant result means the data give strong enough evidence to reject the null hypothesis at the chosen level; it does not prove the alternative, and it says nothing about the size or importance of the effect.

The t-test: comparing two means

The unpaired t-test compares the means of two independent groups, such as mown and unmown quadrats. It works best with roughly normally distributed data and about ten or more values per group.

Worked example

Use a t-test to decide whether mean D differs significantly between the mown and unmown quadrats. Mown: mean 2.65, variance 0.136, n = 10. Unmown: mean 5.65, variance 1.012, n = 10. (Hypothetical data.)

Show the solution

Step 1: hypotheses. H₀: there is no significant difference in mean D between mown and unmown grassland. H₁: there is a significant difference.

t=xˉ1−xˉ2s12n1+s22n2t=n1​s12​​+n2​s22​​​xˉ1​−xˉ2​​

Step 2: substitute. Difference in means = 5.65 − 2.65 = 3.00. Standard error = √(1.012 ÷ 10 + 0.136 ÷ 10) = √(0.1012 + 0.0136) = √0.1148 = 0.339.

Step 3: calculate t. t = 3.00 ÷ 0.339 = 8.86.

Step 4: degrees of freedom and critical value. df = n₁ + n₂ − 2 = 18. The critical value of t for df = 18 at p = 0.05 (two-tailed) is 2.10.

Step 5: decide. 8.86 > 2.10, so H₀ is rejected (software gives p < 0.001). Mean D is significantly higher in unmown grassland than in mown grassland.

Step 6: a check. The two groups have very different variances (1.012 and 0.136). Welch's version of the t-test, which does not assume equal variances, gives the same t here with fewer degrees of freedom and is still highly significant, so the conclusion does not change. Mentioning this check shows understanding in criterion E.

ANOVA: comparing three or more means

ANOVA (analysis of variance) compares the means of three or more groups at once. Using several t-tests instead increases the chance of finding a "significant" difference by luck. ANOVA compares the variation between group means with the variation within groups: if the group means are far apart compared with the scatter inside each group, F is large.

Worked example

An extended design samples five quadrats under each of three regimes (hypothetical data). D values: mown weekly 2.2, 2.6, 2.4, 2.0, 2.3; mown monthly 3.4, 3.0, 3.8, 3.3, 3.5; unmown 5.6, 4.9, 6.2, 5.3, 6.0. Carry out a one-way ANOVA.

Show the solution

Step 1: group means and grand mean. Weekly 2.30; monthly 3.40; unmown 5.60. Grand mean of all 15 values = 3.77.

Step 2: between-group sum of squares. SS_between = Σ n(group mean − grand mean)² = 5(2.30 − 3.77)² + 5(3.40 − 3.77)² + 5(5.60 − 3.77)² = 10.76 + 0.67 + 16.81 ≈ 28.23 (using unrounded means).

Step 3: within-group sum of squares. Sum of squared deviations from each group's own mean: 0.20 + 0.34 + 1.10 = 1.64.

Step 4: mean squares. df_between = 3 − 1 = 2, so MS_between = 28.23 ÷ 2 = 14.12. df_within = 15 − 3 = 12, so MS_within = 1.64 ÷ 12 = 0.137.

Step 5: F. F = 14.12 ÷ 0.137 = 103. The critical value of F for (2, 12) degrees of freedom at p = 0.05 is 3.89.

Step 6: decide. 103 > 3.89, so H₀ (all three means are equal) is rejected. ANOVA shows only that at least one mean differs; a post-hoc test (such as Tukey's test, available in spreadsheets and online calculators) shows which pairs differ. Here all three pairs differ significantly, so diversity rises with each reduction in mowing.

The chi-squared test: associations between categories

The chi-squared test compares observed frequencies (counts) with the frequencies expected if there were no association between two categorical variables. It suits survey data such as "support or oppose" against "age group". It must be used on raw counts, never percentages, and every expected frequency should be at least 5.

Worked example

A group member surveys 120 park users (hypothetical data). Of 40 people aged 12–24, 24 support the reduced-mowing policy and 16 oppose it; of 40 aged 25–59, 18 support and 22 oppose; of 40 aged 60 and over, 10 support and 30 oppose. Test for an association between age group and support.

Show the solution

Step 1: hypotheses. H₀: there is no association between age group and support for reduced mowing. H₁: there is an association.

Step 2: expected frequencies. Expected = (row total × column total) ÷ grand total. Support total = 52, oppose total = 68, each column total = 40. Expected "support" in each age group = 52 × 40 ÷ 120 = 17.33; expected "oppose" = 68 × 40 ÷ 120 = 22.67. All are above 5.

χ2=∑(O−E)2Eχ2=∑E(O−E)2​

Step 3: calculate. Support: (24 − 17.33)² ÷ 17.33 = 2.56; (18 − 17.33)² ÷ 17.33 = 0.03; (10 − 17.33)² ÷ 17.33 = 3.10. Oppose: (16 − 22.67)² ÷ 22.67 = 1.96; (22 − 22.67)² ÷ 22.67 = 0.02; (30 − 22.67)² ÷ 22.67 = 2.37. χ² = 10.05.

Step 4: degrees of freedom. df = (rows − 1) × (columns − 1) = (2 − 1) × (3 − 1) = 2. Critical value at p = 0.05 = 5.99.

Step 5: decide. 10.05 > 5.99, so H₀ is rejected: support depends on age group. The largest contributions come from the youngest group (more support than expected) and the oldest (less), which tells the analysis where the association lies.

Spearman's rank: correlation with ranked data

Spearman's rank correlation (rₛ) measures the strength and direction of a correlation between two variables by ranking each and comparing the ranks. It does not need a straight-line relationship or normally distributed data, only that one variable tends to rise (or fall) as the other rises. Values run from +1 (perfect positive) through 0 (none) to −1 (perfect negative).

Worked example

A trampling transect records the number of plant species in a 0.5 m × 0.5 m quadrat every metre from the edge of a path along a transect (hypothetical data). Distance 0–9 m; species: 2, 4, 3, 5, 7, 6, 8, 11, 9, 10. Calculate rₛ and test its significance.

Show the solution
rs=1−6∑d2n(n2−1)rs​=1−n(n2−1)6∑d2​

Step 1: rank both variables. Distance ranks: 1–10 in order. Species ranks (lowest = 1): 1, 3, 2, 4, 6, 5, 7, 10, 8, 9.

Step 2: differences in rank (d) and d². d = 0, −1, 1, 0, −1, 1, 0, −2, 1, 1; d² = 0, 1, 1, 0, 1, 1, 0, 4, 1, 1. Σd² = 10.

Step 3: calculate. rₛ = 1 − (6 × 10) ÷ (10 × 99) = 1 − 60 ÷ 990 = 1 − 0.061 = 0.94.

Step 4: compare with the critical value. For n = 10 at p = 0.05 (two-tailed), the critical value is about 0.65. 0.94 > 0.65, so there is a significant, strong positive correlation: species richness increases with distance from the path.

Step 5: the limit of the result. Correlation does not show causation. Trampling is the likely cause, but soil moisture, shade or nutrients may also change with distance from the path; the analysis needs to discuss them.

Scatter graph of species per quadrat against distance from a path for hypothetical data, 0 to 9 m: 2, 4, 3, 5, 7, 6, 8, 11, 9, 10. Strong positive relationship; Spearman's rs = 0.94, n = 10, critical value about 0.65.Scatter graph of species per quadrat against distance from a path for hypothetical data, 0 to 9 m: 2, 4, 3, 5, 7, 6, 8, 11, 9, 10. Strong positive relationship; Spearman's rs = 0.94, n = 10, critical value about 0.65.
Hypothetical data. The points rise steadily away from the path with small reversals, a strong monotonic relationship that Spearman's rank describes well.

Definition

Correlation: a statistical relationship between two variables in which one tends to increase (positive correlation) or decrease (negative correlation) as the other increases; a correlation does not by itself show that one variable causes the change in the other.

Pearson's r and R²: linear relationships

The Pearson correlation coefficient (r) measures how closely two continuous variables follow a straight line; like any correlation coefficient, it runs from −1 to +1. It is usually calculated with a spreadsheet (the CORREL function) or a graphing calculator. Its square, the coefficient of determination (R²), gives the proportion of the variation in the dependent variable that is explained by the linear relationship with the independent variable.

Scatter graph for ten hypothetical city districts: land surface temperature falls from about 38 °C at 5% tree cover to 32.6 °C at 48%. Dashed line of best fit y = 38.5 − 0.116x; r = −0.93, R² = 0.87.Scatter graph for ten hypothetical city districts: land surface temperature falls from about 38 °C at 5% tree cover to 32.6 °C at 48%. Dashed line of best fit y = 38.5 − 0.116x; r = −0.93, R² = 0.87.
Hypothetical database sample of ten city districts. Temperature falls as tree cover rises; R² = 0.87 means 87% of the variation in temperature between districts is accounted for by the straight-line relationship with tree cover.

Worked example

For the ten districts in the scatter graph, a spreadsheet gives r = −0.93 and a line of best fit y = 38.5 − 0.116x. Interpret r, R² and the gradient. (Hypothetical data.)

Show the solution

r: −0.93 is a strong negative correlation. For n = 10, the critical value of r at p = 0.05 (two-tailed) is 0.63; 0.93 > 0.63, so the correlation is significant.

R²: r² = (−0.933)² = 0.87 (squaring the rounded −0.93 would give 0.86). About 87% of the variation in land surface temperature between these districts is accounted for by tree cover; 13% is due to other factors (building density, water, surface materials) or measurement error.

Gradient: −0.116 °C per percentage point of tree cover, so each 10 percentage points of extra cover is associated with about 1.2 °C lower surface temperature in this sample. The relationship should not be extended beyond the range measured (5–48% cover).

Spreadsheets and free online calculators perform all of these tests correctly and quickly. Using them is fine; what earns marks is choosing the right test, stating the hypotheses, reporting the statistic, degrees of freedom or n, the critical value or p-value, and interpreting the result in words. Show one calculation in full, or the output with its inputs, so the processing can be checked.

Common mistakes in criterion D

Common mistake

Presenting a page of raw data and one graph, but never calculating anything that answers the research question (no index, no means, no test). The processing must produce findings that fully address the question: for a comparison, at least the means, a measure of spread and a suitable test.

Mistake

Fix

Units missing from headings, or put in every cell

Quantity and unit once in the column heading: "Dissolved oxygen / mg L⁻¹"

Inconsistent decimal places (2.1, 2.45, 3)

Match the precision of the measurement throughout a column

Chi-squared on percentages, or with expected values below 5

Use raw counts; combine categories or collect more responses

Graphs with default spreadsheet titles ("Series 1") and no axis labels

A descriptive title, labelled axes with units, a legend only when needed

YouTube
IB ESSentials with Mr Kremer: presenting and processing raw data for criterion D, including tables, graphs and statistics.

Checklist for criterion D

  • To do:

    Raw data tables have titles, headings with units, consistent precision and qualitative notes; a sample is shown, the rest in an appendix.

  • To do:

    One worked example of each calculation is shown (e.g. one value of D).

  • To do:

    Processed data include means (or medians) and a measure of spread for each group.

  • To do:

    Graphs suit the data, with titles, labelled axes, units and stated error bars.

  • To do:

    A suitable statistical test is chosen and justified, with hypotheses, the statistic, degrees of freedom or n, and the critical value or p-value.

  • To do:

    The processing answers the research question directly.

Criterion E: analysis and conclusion

Criterion E assesses how well you interpret the data in ways relevant to the research question: the patterns are highlighted, interpreted correctly and used to reach a valid conclusion.

Band

Analysis

Conclusion

1–2

Identifies patterns or trends relevant to the research question

Does not address the research question, or is not supported by the analysis

3–4

Describes relevant patterns or trends, including some measures of bias, reliability, validity and uncertainty

Addresses the research question and is partially supported by the analysis

5–6

Explains all relevant patterns and trends, including measures of bias, reliability, validity and uncertainty

Addresses the research question and is supported by the analysis

Three features move an analysis into the top band. It explains the patterns (gives the ecological, physical or social reasons for them) rather than only describing them. It deals with all the relevant patterns, including the awkward ones (the outlier, the unexpected spread, the group that did not behave as predicted). And it judges the quality of the data, through bias, reliability, validity and uncertainty, before deciding how far the conclusion can be trusted.

Identify, describe, explain

Level

Example from the worked investigation

Identifies

"Unmown grassland had higher diversity."

Describes

"Mean D was 5.65 in unmown grassland and 2.65 in mown grassland, more than twice as high, and the difference was significant (t = 8.86, df = 18, p < 0.001). Unmown quadrats were also more variable (SD 1.01 against 0.37)."

Explains

"Mowing every two weeks removes the leaves and flowering stems of taller species, so only low-growing rosette plants such as daisy and dandelion persist, and they dominate the counts; this keeps both richness and evenness, and therefore D, low. Without mowing, taller species such as yarrow and bird's-foot trefoil can establish, and competition is spread among more species. The higher variability in unmown quadrats suggests that the community is still changing after only one season without mowing, with some patches colonised by new species and others still dominated by clover."

Explanations come from ESS ideas (succession, disturbance, competition, niches, limiting factors, perspectives) and from the published studies in the background. Returning to those studies in the analysis, and saying whether your results agree with them and why they might differ, is one of the clearest signs of a strong analysis.

Bias, reliability, validity and uncertainty

A supported conclusion includes measures of bias, reliability, validity and uncertainty. These four words are often used loosely; in an investigation each has a precise meaning and a practical way to judge it.

Term

Meaning

How to judge it in the worked example

Bias

A systematic distortion of the data or results in one direction

Random coordinates reduce sampling bias; counting only broadleaved plants is a source of bias in D

Reliability

The consistency of the results: whether repeated measurements or a repeat of the investigation would give similar values

Spread within each zone (SD); a second count of two quadrats by a partner agreed to within one plant per species

Validity

Whether the method measures what it claims to measure and the conclusion follows from the data

Does D of broadleaved plants measure "plant diversity"? Are the zones different only in mowing?

Uncertainty

The range within which the true value is likely to lie, from measurement limits and from sampling

SD and error bars; the p-value; uncertain identifications (two plants recorded as "species A")

Definition

Validity: the extent to which an investigation measures what it sets out to measure and its conclusions are justified by the data, which depends on controlling other variables and on choosing appropriate indicators.

Two further pairs of ideas help to discuss data quality. Accuracy is how close a measurement is to the true value, while precision is how close repeated measurements are to each other (and the smallest division an instrument can read). Random error causes unpredictable scatter around the true value and is reduced by larger samples and repeats; systematic error shifts every value in the same direction (a miscalibrated pH meter, always counting each rooted clover shoot as a separate plant) and is not reduced by repeating the measurement.

Definition

Systematic error: an error that shifts all measurements in the same direction by a similar amount, caused by the equipment, the method or the observer, and not reduced by repeating measurements.

An outlier is a value that lies far from the rest of its group. In the worked example, unmown quadrat 9 (D = 3.9) is the lowest in its zone; the field notes record that it lay in a patch of dense white clover. An outlier should be investigated, not deleted: if there is a clear reason it does not belong to the population (an equipment fault, a quadrat placed on a path), it may be excluded with that reason stated; if it is a real part of the variation, it stays in and is explained.

A common rule of thumb treats values more than 1.5 × IQR beyond the quartiles as outliers; by that rule, 3.9 (above 5.1 − 1.8 = 3.3) is not one.

Common mistake

Using "reliable" to mean "good" and "accurate" to mean "correct" in every sentence ("The results were reliable and accurate because I was careful"). Each term needs evidence: reliability from repeats or the spread of data, accuracy from comparison with a known value or calibration, validity from the control of variables and the choice of indicator.

Correlation and causation

A significant correlation shows that two variables change together, not that one causes the other. Tree cover and surface temperature may both be linked to a third factor (wealthier districts may have both more trees and lower building density). Field comparisons are similar: the unmown zone may differ from the mown zone in ways other than mowing. Causation is better supported when there is a known mechanism, when other variables were controlled or monitored, and when the result agrees with experimental studies. The analysis should say how far these conditions are met.

Writing the conclusion

The conclusion answers the research question directly, in one or two sentences, with the key numbers and the result of the statistical test. It states whether the null hypothesis was rejected, links the result to the ESS theory and the published studies, and is honest about how far the data support it, given the bias, reliability, validity and uncertainty already discussed. A short final link back to the strategy from criterion B ("the results support the council's policy, at least in its first year") is valuable, as long as it does not claim more than the data show.

Worked example

Write a conclusion for the worked example and assess it against criterion E. (Hypothetical data.)

Show the model conclusion and assessment

Model conclusion. "In one town park in June, plant species diversity of broadleaved plants was significantly higher in grassland unmown since April (mean D = 5.65, SD = 1.01) than in grassland mown every two weeks (mean D = 2.65, SD = 0.37; t = 8.86, df = 18, p < 0.001), so the null hypothesis is rejected."

"The difference agrees with the published finding that less frequent mowing increases the number of flowers in lawns, and is explained by the removal of disturbance that had allowed a few low-growing species to dominate. The conclusion is limited to broadleaved plants (grasses were not counted), to one park and to one month, and the higher variability of unmown quadrats suggests that the community is still changing. Within these limits, the results support the council's reduced-mowing strategy as a way to increase plant diversity in its first year."

Assessment: 5–6 band (6 marks), provided the analysis before it explains all the patterns. The conclusion answers the question with the numbers and the test result, states the outcome for H₀, explains the pattern with theory, compares with published work, and states its own limits (validity of D for "plant diversity", scope of the data, uncertainty from variability). It is fully supported by the analysis.

A weak conclusion on the same data shows how easily a conclusion can claim more than the data allow.

Worked example

Weak conclusion: "My hypothesis was correct. Not mowing grass increases biodiversity, so all councils should stop mowing their parks." Assess it against criterion E.

Show the assessment

Assessment: 1–2 band. The conclusion does not give any numbers or the result of the test, so it is not shown to be supported by the analysis. It over-generalises from broadleaved plants in one park in one month to "biodiversity" everywhere, and recommends a policy that ignores both the limits of the data and the social tension discussed in criterion B. "Correct" is the wrong word: data can support a hypothesis or lead to rejecting the null hypothesis, but they do not prove a hypothesis correct.

Exam tip

Answer the research question in the first sentence of the conclusion, using the same words as the question. A moderator should be able to read the question and the first sentence of the conclusion side by side and see a direct answer.

Checklist for criterion E

  • To do:

    Every relevant pattern and trend is described with numbers from the processed data, including spread and any outliers.

  • To do:

    Each pattern is explained using ESS theory and compared with the published studies from the background.

  • To do:

    The result of the statistical test is interpreted in words, with the outcome for the null hypothesis.

  • To do:

    Bias, reliability, validity and uncertainty are each discussed with evidence from the investigation.

  • To do:

    Correlation is not presented as causation.

  • To do:

    The conclusion answers the research question directly, with key numbers, and claims no more than the data support.

Criterion F: evaluation

Criterion F assesses how well you evaluate the investigation itself: the method, the data and the conclusion that rests on them.

Band

Weaknesses and limitations

Improvements

Unresolved questions

1–2

States generic weaknesses or limitations that affect the conclusion

States improvements that address them

States generic questions arising from the investigation

3–4

Describes weaknesses or limitations that affect the conclusion

Describes improvements that address them

Outlines questions arising from the investigation

5–6

Evaluates specific weaknesses or limitations that affect the conclusion

Evaluates improvements that address them

Describes questions arising, as they affect the conclusion

Two distinctions matter. A generic weakness could apply to almost any investigation ("human error", "more time", "a bigger sample"); a specific weakness belongs to this method and this data ("grasses were not counted, so D does not include the most abundant plants in either zone"). And there is a difference between methodological weaknesses and limitations.

Methodological weakness

Limitation

What it is

A problem with how the investigation was carried out: control of variables, or the precision of measurements

A restriction on how far the conclusion can be applied: the range or scope of the data, the boundaries of the system studied, or the assumptions made

Worked example

Counting individual plants of creeping species (clover, buttercup) is imprecise, because one plant can root at several points

One park, one June, broadleaved plants only: the conclusion cannot be applied to grasses, to other parks or to later years

Typical improvement

Measure percentage cover for creeping species, or count rooted shoots by a stated rule

Sample several parks, repeat in later summers, include grasses

Definition

Methodological weakness: a flaw in how an investigation was carried out, such as poor control of variables or imprecise measurement, that reduces the quality of the data and the confidence in the conclusion.

The two kinds of problem call for different responses: a weakness is fixed by changing the method, a limitation by widening the scope of the data.

Definition

Methodological limitation: a restriction on the scope of an investigation's conclusion, arising from the range of data collected, the boundaries of the system studied or the assumptions made.

Evaluating, not just listing

To evaluate a weakness is to judge its importance: how it affected the data, in which direction, how much it matters for the conclusion, and how confident the conclusion can still be. To evaluate an improvement is to judge whether it is realistic, what it would cost in time or equipment, and what difference it would make. Unresolved questions are the questions the investigation could not answer, described in terms of how they affect the conclusion (and, often, the strategy).

Five linked boxes for evaluating a weakness: 1 the specific weakness (grasses not counted), 2 its effect on the data, 3 its effect on the conclusion, 4 an improvement (count flowering grasses), 5 an evaluation of the improvement.Five linked boxes for evaluating a weakness: 1 the specific weakness (grasses not counted), 2 its effect on the data, 3 its effect on the conclusion, 4 an improvement (count flowering grasses), 5 an evaluation of the improvement.
Evaluating one weakness fully: what it was, what it did to the data, what it means for the conclusion, how to fix it and whether the fix is worth it. Three weaknesses handled this way score more than ten listed.

Specific weakness or limitation

Effect on data and conclusion

Improvement, evaluated

Grasses not counted (weakness of validity)

D measures broadleaved diversity only. Unmown grassland probably also has more flowering grass species, so the real difference in total plant diversity may be larger; but if tall grasses dominate unmown areas, evenness could be lower. The direction is uncertain, so the conclusion is restricted to broadleaved plants.

Identify grasses from their flowering heads in late June, when most are in flower. Realistic with a grass key and training; adds about 10 minutes per quadrat.

Counting individuals of creeping species (precision)

One clover plant may be counted as several, inflating n for clover and lowering D in clover-rich quadrats (likely in both zones, so a smaller effect on the difference).

Use percentage cover for creeping species; but D needs counts, so a cover-based index would have to replace D. A clear counting rule (each rooted shoot counts as one) is the more realistic fix.

Only two zones in one park (limitation of scope)

The zones may differ in ways other than mowing (soil, history, trampling), so the difference cannot be attributed with certainty to mowing alone.

Sample paired mown and unmown areas in three or more parks; the strongest fix, but it triples the fieldwork.

Unresolved questions arise naturally from these points, and the strongest are tied to the conclusion and the strategy. Does the higher diversity last, increase or fall back after several years of the policy? Does higher plant diversity actually lead to more pollinators, which is the aim of the strategy? Do the gains depend on removing the cut hay, as the council does, or would leaving it make a difference? Each one marks a point at which the conclusion stops.

Worked example

Weak evaluation: "There may have been human error when counting. I could have done more quadrats and gone to more parks. Next time I would use better equipment. A question is whether this is true everywhere." Assess it against criterion F and rewrite one weakness so that it reaches the top band.

Show the assessment

Assessment: 1–2 band. The weaknesses are generic ("human error", "better equipment"), the improvements are stated without saying how they would help or whether they are realistic, and the unresolved question is generic.

Rewritten weakness (5–6 band): "Grasses were not counted, because most were not in flower and could not be identified reliably. D therefore measures broadleaved diversity only. Because unmown areas may contain more flowering grass species but also taller, more dominant grasses, the true difference in total plant diversity could be larger or smaller than measured, so the conclusion is limited to broadleaved plants. Sampling in late June, when most grasses flower, and identifying them with a grass key would remove this limitation; it is realistic, adding about ten minutes per quadrat, and would allow a conclusion about all plants."

Tip

Write evaluation notes during data collection, not afterwards: every problem met in the field ("clover patches hard to count", "rain on day 2", "two people disagreed over a plant") is a specific weakness ready to evaluate. Problems remembered weeks later tend to come out generic.

Checklist for criterion F

  • To do:

    Three or four specific weaknesses and limitations are chosen, each belonging to this investigation.

  • To do:

    For each: its effect on the data, the likely direction and size of that effect, and what it means for the conclusion.

  • To do:

    Each weakness has a realistic improvement, evaluated for feasibility and likely effect.

  • To do:

    Limitations of scope (one site, one time, one group of organisms or people) are stated as limits on the conclusion.

  • To do:

    Unresolved questions are described in relation to the conclusion and, where possible, the strategy.

Final checks before submission

Add to your notes: one line per criterion to check the finished report: A, the issue explained with sources and one focused question; B, a described strategy and one explained tension; C, a method someone else could repeat, with enough data; D, clear tables and graphs, correct processing, a suitable test; E, every pattern explained, with bias, reliability, validity and uncertainty, and a direct conclusion; F, specific weaknesses evaluated, realistic improvements, unresolved questions.

  • To do:

    The title, candidate code(s) and word count are at the top, and the report is within 3,000 words.

  • To do:

    Each criterion has a clearly headed section.

  • To do:

    Every number in the analysis and conclusion matches the processed data tables.

  • To do:

    Every graph and table is referred to in the text.

  • To do:

    All sources are referenced and the references are complete.

  • To do:

    The final version takes account of the teacher's comments on the draft.

Common mistake

Leaving the evaluation until the last evening. Criterion F is worth as much as criterion D or E, and evaluations written in a hurry are almost always generic. Plan to have the full draft, evaluation included, ready for the teacher's single round of feedback.

Keep your place

In Augment the notes remember where you stopped and which pages you have finished.

Open in Augment

More IB ESS notes

  • Criteria B and C: strategy and methodThe page before this.
  • IB ESSThe ESS syllabus, how it is assessed and every notes page.

Carry on with ESS in Augment

With a free account, Augment remembers where you stopped in the notes and which questions you have marked.

Start free