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  3. Paper 2: data, short answers and extended responses

Paper 2: data, short answers and extended responses

How to answer Paper 2: data analysis and short answers in Section A, and choosing, planning and writing extended responses in Section B.

  • IB Biology
  • Exam skills
  • SL and HL

13 min readLast reviewed 14 Oct 2026

Paper 2 is a single booklet in two sections. Section A has data-based and short-answer questions across the whole course. Section B has extended-response questions, from which you choose: SL candidates answer one of two, HL candidates two of three. Section A rewards precise, short answers tied to data; Section B rewards planned, well-organised answers that cover every part of the question.

At SL, Paper 2 lasts 1 hour 30 minutes and is worth 50 marks: 34 in Section A and 16 in Section B. At HL it lasts 2 hours 30 minutes and is worth 80 marks: 48 in Section A and 32 in Section B, from two questions of 16 marks each. Paper 2 carries 44% of the final grade at both levels.

Both sections draw on the same knowledge as Paper 1. None of the questions is multiple choice, so every mark depends on what you write, draw or calculate.

Section A: data analysis and short answers

Section A usually opens with a longer data-based question, built on several linked data sets from published research or experiments, followed by structured questions on different parts of the course. Each structured question is split into short parts, each with its own command term and a small number of marks.

The data-based question

The data-based question gives two to five related figures or tables and asks a series of questions that move from reading the data to explaining and evaluating it. Later parts often ask you to combine information from two figures, so it pays to read every figure and its caption before writing.

  1. Read the introduction: what organism, what was measured, and what each figure shows.

  2. For each figure, read the title, axes, units and key, and note the main trend in the margin.

  3. Answer each part in order, with values and units from the data.

  4. Where a part says "using the data" or "with reference to figure 2", quote from that figure.

  5. Use your biology to explain trends, but keep the explanation tied to the context given.

A student counted stomata on the upper and lower surfaces of ten leaves of one species of broad-leaved plant, using nail-varnish impressions viewed under a light microscope. The results, a practice data set, are shown in the table.

Leaf surface

Mean stomatal density / mm⁻²

Standard deviation / mm⁻²

Number of leaves

Upper (adaxial)

38

9

10

Lower (abaxial)

210

18

10

Worked example

Using the table of stomatal density on the two leaf surfaces:

(a) Calculate the percentage difference between the mean stomatal densities of the two surfaces. [2]

(b) Compare the stomatal density of the two surfaces. [2]

(c) Explain the advantage to the plant of having most of its stomata on the lower surface. [3]

(d) Suggest why the student measured ten leaves rather than one. [1]

Show the markscheme
  • (a) Percentage difference compares two values with their mean: 210−38(210+38)÷2×100(210+38)÷2210−38​×100 [1] =139%=139% (accept 138.7%) [1].

  • (b) The lower surface has a much higher mean density than the upper surface (210 compared with 38 mm⁻², about 5.5 times as many) [1]; there is more variation on the lower surface (SD 18 compared with 9 mm⁻²) [1]; the SD ranges do not overlap, so the difference is likely to be significant [1]. [max 2]

  • (c) The lower surface is shaded / cooler / less exposed to wind [1]; so less water is lost by transpiration through stomata there [1]; while gas exchange (CO₂ uptake for photosynthesis) can still take place [1]. [3]

  • (d) Stomatal density varies between leaves / to give a reliable mean / to allow standard deviation to be calculated. [1]

Exam tip

When a Section A part says "compare", write sentences that mention both items with values from the data, such as "the lower surface had 210 mm⁻² compared with 38 mm⁻² on the upper surface". Two separate sentences, one about each surface, may be credited only once.

Short-answer questions

The short-answer questions test recall and understanding across all four themes. Typical stems are "label the diagram", "outline the role of", "explain how", "compare and contrast", "draw a molecular diagram of" and "annotate the graph to show". Answers should be as long as the marks require and no longer: one precise point per mark.

Stem

Marks

What a full-mark answer contains

State the name of the bond formed between two amino acids.

1

Peptide bond.

Outline the role of ATP synthase in the mitochondrion.

2

Enzyme in the inner membrane; uses the flow of H⁺ through it to make ATP from ADP and phosphate.

Explain how the structure of the alveolus is adapted to gas exchange.

3

Three features, each with its function: one cell thick (short diffusion distance); large total surface area; dense capillary network maintaining a concentration gradient.

Compare and contrast the structure of DNA and RNA.

3

One similarity and two paired differences: both are polymers of nucleotides; deoxyribose versus ribose; thymine versus uracil; double-stranded versus single-stranded.

Drawing and sketching in Section A

Section A often asks for a drawing: a molecular diagram (glucose, an amino acid, a dipeptide, a phospholipid), a diagram from a micrograph, a pedigree chart, a Punnett grid, a cladogram or an energy pyramid. Marks go to named features drawn correctly and labelled clearly.

  • Molecular diagrams: every atom and bond shown, OH and H groups on the correct carbons, the correct ring form (α- or β-glucose), the bond that joins two units labelled.

  • Diagrams of structures: the features the question names, in the right positions and proportions, with ruled label lines that touch the structure.

  • Sketch graphs: labelled axes with variables (units if known), the correct shape and the key features labelled.

Sketching a graph from memory is a common Section A task. The oxygen dissociation curve for adult haemoglobin is a typical example, with its HL extension, the Bohr shift.

02468101214020406080100pO₂ / kPaSaturation / %
  • Normal CO₂
  • Higher CO₂ (Bohr shift, HL)
General shape of the oxygen dissociation curve for adult haemoglobin. A sketch earns marks for labelled axes, the S shape and a plateau near 100% saturation; at higher CO₂ the curve shifts to the right.

Worked example

Sketch the oxygen dissociation curve for adult haemoglobin. On the same axes, sketch the curve at a higher carbon dioxide concentration. (HL) [3]

Show the markscheme
  • Axes labelled: partial pressure of oxygen (x) and percentage saturation of haemoglobin (y) [1].

  • S-shaped (sigmoid) curve that levels off close to 100% [1].

  • Second curve to the right of the first / lower saturation at the same pO₂ [1].

Exact values are not needed in a sketch, but the shape must be clear. A straight line or a curve with no plateau loses the second mark. The curves are taught in B3.1 Gas exchange.

Common mistake

Using "it" and "this" in short answers, as in "it binds to it and this changes its shape". The marker cannot credit a point unless the molecule or structure is named. Write "the substrate binds to the active site, which changes the shape of the enzyme".

Section B: extended responses

Each Section B question is worth 16 marks. Fifteen are for the content, split between labelled parts, typically three, such as 4 + 4 + 7 or 3 + 5 + 7; the sixteenth is for the quality of the answer as a whole. The parts usually move from describe or outline to explain or discuss, and they often draw on more than one theme. A question might start with protein structure and end with a gene mutation, or start with the structure of a leaf and end with the global carbon cycle.

Choosing questions

The choice is one of the few decisions that can change your Paper 2 mark by several marks at once. Spend a few minutes on it.

  1. Read every part of every Section B question, not just the first part.

  2. For each question, ask whether you can answer the part with the most marks well, because that part decides most of the score.

  3. Check the command terms: an "explain" or "discuss" part needs reasons and balance, not just facts you remember.

  4. Choose the question where you can write the most distinct, correct points across all its parts.

Common mistake

Choosing a question because its first part is easy. A 4-mark "describe" that you can answer perfectly is worth less than the 7-mark "explain" that follows it. Judge the whole question.

How Section B is marked

Section B markschemes are lists of acceptable points for each part, with a maximum for the part. There are usually more points listed than marks available, so an answer can reach full marks without making every point. Each point is credited once: repeating an idea in different words does not add marks. Points written in the wrong part may not be credited, so answer each part under its own label.

One mark of the 16 is awarded for the quality of the whole answer. It is given when the answer is clear enough to be followed without rereading, is concise, and has little or no repetition or irrelevant material. Writing one idea per sentence, with the correct terms throughout, earns this mark and also makes each content point easier to credit.

Tip

Aim for about one and a half times as many distinct points as there are marks: about six points for a 4-mark part and ten or eleven for a 7-mark part. This allows for points that turn out not to be on the markscheme.

Planning and structuring an answer

A plan of one or two minutes for each part prevents both padding and missing points. Write it as a list of key words in the margin or on the planning space, and tick each item off as you use it.

  1. Underline the command term and the scope of each part ("in humans", "with reference to one example").

  2. List the points you can make for the part, then order them logically: structure before function, cause before effect, steps in sequence.

  3. Write one point per sentence, using technical terms.

  4. Include a labelled diagram where it carries marks more quickly than words (a membrane, a nephron, a cladogram), and refer to it in the text.

  5. For "discuss" and "evaluate", plan points on both sides and a final judgement.

  6. Leave a few minutes at the end to reread for missing words and contradictions.

Exam tip

A labelled diagram can earn marks in Section B, often several at once, but only for features that are labelled. Label each structure the markscheme is likely to list, and annotate with function where the part asks for function.

A worked extended-response question

The question links three subtopics: DNA structure (A1.2 Nucleic acids), DNA replication (D1.1) and the effect of a mutation on a protein and on the phenotype (D1.2 Protein synthesis, D1.3 Mutation and gene editing, B1.2 Proteins). It is set at SL; an HL paper might replace part (b) with the roles of the specific replication enzymes.

Worked example

(a) Describe the structure of a DNA molecule. [4]

(b) Outline how DNA is replicated. [4]

(c) Explain how a change to one base in a gene can lead to a change in the phenotype of an organism, using sickle cell anaemia as an example. [7]

Total [16]: 15 marks for content and 1 mark for the quality of the answer.

Show the model answer and markscheme

Model answer

(a) DNA is a polymer made of two strands of nucleotides. Each nucleotide consists of a phosphate group, the sugar deoxyribose and one of four nitrogenous bases: adenine, thymine, cytosine or guanine. The nucleotides in each strand are joined by covalent bonds between the sugar of one nucleotide and the phosphate of the next, forming a sugar–phosphate backbone. The two strands are antiparallel and are held together by hydrogen bonds between complementary bases, adenine with thymine and cytosine with guanine. The two strands are wound into a double helix.

(b) DNA replication is semi-conservative. Helicase unwinds the double helix and separates the two strands by breaking the hydrogen bonds between bases. Each strand then acts as a template. Free nucleotides pair with the exposed bases by complementary base pairing, and DNA polymerase links them into a new strand. Each new DNA molecule contains one original strand and one new strand, so the two molecules are identical in base sequence.

(c) A gene is a sequence of bases that codes for a polypeptide. In sickle cell anaemia, a base substitution in the gene for the β-globin chain of haemoglobin changes the codon GAG to GTG. When the gene is transcribed, the mRNA carries the codon GUG instead of GAG. During translation, GUG codes for valine instead of glutamic acid, so the sixth amino acid of the β-globin polypeptide is valine. This change in primary structure alters the properties of the haemoglobin, which is called haemoglobin S. At low oxygen concentrations, molecules of haemoglobin S bind together into long fibres. The fibres distort red blood cells into a rigid sickle shape. Sickle cells carry less oxygen, are destroyed faster than normal red blood cells, causing anaemia, and can block capillaries, causing pain and damage to tissues. The change in a single base has therefore changed the phenotype at the level of the molecule, the cell and the whole organism.

Markscheme

(a) [max 4]

  • nucleotides made of phosphate, deoxyribose and a base [1]

  • four bases named: adenine, thymine, cytosine, guanine [1]

  • sugar–phosphate backbone / covalent bonds between sugar and phosphate [1]

  • two strands, antiparallel [1]

  • complementary base pairing, A with T and C with G [1]

  • hydrogen bonds between bases [1]

  • double helix [1]

(b) [max 4]

  • semi-conservative replication [1]

  • helicase unwinds / separates strands [1]

  • by breaking hydrogen bonds [1]

  • each strand acts as a template [1]

  • free nucleotides pair by complementary base pairing [1]

  • DNA polymerase links nucleotides / forms the new strand [1]

  • two identical DNA molecules produced [1]

(c) [max 7]

  • gene is a base sequence coding for a polypeptide [1]

  • base substitution / point mutation [1]

  • in the gene for β-globin / haemoglobin [1]

  • GAG changed to GTG (DNA) / GAG to GUG (mRNA) [1]

  • changed codon transcribed into mRNA [1]

  • translation gives valine instead of glutamic acid [1]

  • at the sixth amino acid / change in primary structure [1]

  • haemoglobin S forms fibres / polymerises at low oxygen concentration [1]

  • red blood cells become sickle-shaped / rigid [1]

  • less oxygen carried / anaemia / cells destroyed faster [1]

  • sickle cells block capillaries / cause pain or tissue damage [1]

  • phenotype changed at molecular, cellular and whole-organism level [1]

Quality of the answer [1]: the answer is clear enough to follow without rereading, concise, and has little or no repetition or irrelevant material. Total [16].

The model answer reaches the maximum in each part. Part (a) is a description, so it lists features without reasons. Part (b) outlines the steps in order. Part (c) is an explanation: each sentence is a link in a chain from base to codon, codon to amino acid, amino acid to protein, protein to cell and cell to organism, which is why it can collect seven separate marks. The sixteenth mark is for the quality of the whole answer: here, each part is answered under its own label, in a logical order, with no repetition.

Common mistake

Padding an extended response with everything known about the topic. In part (c), a paragraph on the inheritance of sickle cell anaemia or its link with malaria earns nothing, because the question asks how the mutation changes the phenotype. Answer the command term and the scope, then stop.

Common reasons for lost marks in Paper 2

Problem

What it looks like

What to do instead

Describing instead of explaining

"The rate increases and then levels off."

Add the cause of each change: "because light is no longer the limiting factor".

Unpaired comparisons

A paragraph on mitosis and a paragraph on meiosis.

Pair every point, or use a table.

Vague data description

"It goes up."

Quote the values, units and range: "from 4.2 to 14.3 cm³ between 10 and 40 °C".

Imprecise terms

"Energy is produced"; "the enzyme dies"; "water moves down a concentration gradient".

"ATP is produced"; "the enzyme is denatured"; "water moves from higher to lower water potential".

Teleology

"Bacteria become resistant in order to survive."

"Resistant bacteria survive and reproduce, so the allele for resistance becomes more common."

Skipping part of a question

One side of "discuss", or no judgement in "evaluate".

Plan both sides and a conclusion before writing.

Exam tip

At HL, Section B answers on AHL content are marked against HL-level points. An answer on DNA replication that names only helicase and DNA polymerase may score full marks at SL but not at HL, where primase, DNA polymerase I, DNA polymerase III, ligase, Okazaki fragments and 5′ to 3′ direction are expected.

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