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  3. Paper 3: extended problem solving

Paper 3: extended problem solving

What the two long investigative questions on HL Paper 3 look like, how they move from cases to conjecture to proof, and how to keep earning marks when a part is out of reach.

  • IB Mathematics: Analysis and Approaches
  • Exam skills
  • HL only

11 min readLast reviewed 14 Oct 2026

Paper 3 is sat by HL students only. It consists of two long, compulsory questions, each worth roughly half of the paper's marks, and a GDC is allowed throughout. Each question is a guided investigation: it introduces a situation, asks for some concrete cases to be worked out, leads towards a pattern or general result, and then asks for that result to be proved, extended or applied. The paper rewards the habits of a mathematician at work: exploring, conjecturing, generalising and proving.

The mathematics used is the content of the course, at SL and HL, often from several topics in one question. A question may introduce a new idea or a new piece of notation, define it fully, and then ask for it to be used. Nothing outside the course is assumed, but the setting is usually unfamiliar.

How a Paper 3 question is built

A Paper 3 question is long, often a page or more of question text with many parts, but it is carefully scaffolded. The parts follow a predictable arc.

Stage

What the parts ask

Typical command terms

Getting started

Compute simple cases, fill in a table, draw a graph for a particular value

write down, find, calculate, sketch

Spotting a pattern

Describe what the cases have in common; suggest a general formula

suggest, describe, predict

Proving

Prove the conjecture, often by induction or by algebra in general

show that, prove

Extending

Apply the result to a new case, generalise to another parameter, or find a limit

hence, deduce, determine

Reflecting

Comment on a model, explain why a method fails, or justify a restriction

explain, justify, comment

The first parts are routine and carry a fair share of the marks. Almost every student can earn them, so they should never be skipped, even when the question looks unfamiliar.

Exam tip

Paper 3 has the same pace as the other papers: a little more than one minute per mark. With two questions worth a similar number of marks, aim to spend roughly half the time on each. If one question stalls, move to the other and come back; the later parts of a question often do not depend on the stalled part.

Reading the question as a whole

Use the reading time to read both questions from the first line to the last. Paper 3 questions tell a story, and seeing where it ends makes the early parts easier to understand. A final part that says "prove that the area is always less than 1221​" shows what all the earlier parts are building towards.

While reading, look for:

  • definitions and notation introduced by the question, which must be used exactly as defined

  • printed results ("show that…", "given that…"), which can be used later even if they cannot be proved

  • parts that look independent of earlier work, which are safe places to earn marks if a middle part is difficult

  • the general case, usually a parameter such as nn or kk, which the question is leading towards.

Exploring with special cases

The early parts of a Paper 3 question ask for particular cases: n=1,2,3,4n=1,2,3,4, or a specific value of a parameter. Work these out carefully and lay them out so a pattern can be seen, usually in a table. Leave fractions unsimplified if that shows the pattern more clearly, and use the GDC for any heavy arithmetic.

Worked example

Let Sn=∑r=1n1r(r+1)Sn​=r=1∑n​r(r+1)1​, for n∈Z+n∈Z+.

(a) Find S1S1​, S2S2​, S3S3​ and S4S4​.

(b) Hence suggest an expression for SnSn​ in terms of nn.

(c) Prove your conjecture by mathematical induction.

(d) Hence find the limit of SnSn​ as n→∞n→∞.

Show the solution

(a) Add one term at a time.

S1=12,S2=12+16=23,S3=23+112=34,S4=34+120=45S1​=21​,S2​=21​+61​=32​,S3​=32​+121​=43​,S4​=43​+201​=54​

(b) The numerator matches nn and the denominator is one more.

Sn=nn+1Sn​=n+1n​

(c) Let P(n)P(n) be the statement Sn=nn+1Sn​=n+1n​.

When n=1n=1: S1=12S1​=21​ and 11+1=121+11​=21​, so P(1)P(1) is true.

Assume P(k)P(k) is true for some k∈Z+k∈Z+, that is, Sk=kk+1Sk​=k+1k​. Then

Sk+1=Sk+1(k+1)(k+2)=kk+1+1(k+1)(k+2)=k(k+2)+1(k+1)(k+2)Sk+1​=Sk​+(k+1)(k+2)1​=k+1k​+(k+1)(k+2)1​=(k+1)(k+2)k(k+2)+1​
=k2+2k+1(k+1)(k+2)=(k+1)2(k+1)(k+2)=k+1k+2=(k+1)(k+2)k2+2k+1​=(k+1)(k+2)(k+1)2​=k+2k+1​

This is P(k+1)P(k+1). Since P(1)P(1) is true and P(k)P(k) true implies P(k+1)P(k+1) true, P(n)P(n) is true for all n∈Z+n∈Z+ by the principle of mathematical induction.

(d) Divide the numerator and denominator by nn.

Sn=11+1n→1 as n→∞Sn​=1+n1​1​→1 as n→∞

This short question follows the full arc: cases, conjecture, proof, consequence. Real Paper 3 questions are longer and less obvious, but the shape is the same.

Tip

State a conjecture as a precise mathematical statement with its domain: "Sn=nn+1Sn​=n+1n​ for all n∈Z+n∈Z+". A sentence such as "the answer is always one less on top" is too vague to prove and may not earn the mark.

Conjecture and proof

A conjecture is a statement believed to be true on the evidence of cases, but not yet proved. Paper 3 often asks for one and then asks for a proof, which may use any method from the course.

Choosing a method of proof

  • Induction suits statements about every positive integer nn, especially sums, products, derivatives of order nn and divisibility (see 1.15).

  • Direct algebra suits statements about a general parameter kk in a function, where the proof is a calculation done with letters instead of numbers.

  • Contradiction suits statements of impossibility: that something is irrational, or that no value of a parameter works.

  • A counterexample is enough to show that a general statement is false.

Common mistake

Treating a list of checked cases as a proof. Showing that a formula works for n=1,2,3,4n=1,2,3,4 and 55 supports a conjecture, but proves nothing about n=6n=6. When a question says "prove", the argument must cover every case allowed.

Writing an induction proof that earns full marks

Induction proofs appear frequently on Paper 3, and their marks are given for structure as much as for algebra. A complete proof has four parts, each written out:

  1. The base case. Show the statement is true for the first value, evaluating both sides separately.

  2. The assumption. "Assume the statement is true for n=kn=k, for some k∈Z+k∈Z+", with the statement written out for kk.

  3. The inductive step. Starting from one side of the statement for n=k+1n=k+1, use the assumption to reach the other side. Show every line of algebra.

  4. The conclusion. A sentence that refers to both the base case and the inductive step.

Exam tip

The conclusion carries a reasoning mark, and it is usually only awarded when the base case and the inductive step have both been attempted. Write the full sentence: "Since the statement is true for n=1n=1, and true for n=kn=k implies true for n=k+1n=k+1, it is true for all n∈Z+n∈Z+ by mathematical induction."

Generalising with a parameter

The other common shape of a Paper 3 question studies a family of functions or curves that depend on a parameter. The first parts use one or two particular values; later parts ask what happens for every value of the parameter.

Worked example

For k>0k>0, let fk(x)=xe−kxfk​(x)=xe−kx.

(a) Use your GDC to find the coordinates of the maximum point of the graph of f1f1​ and of f2f2​.

(b) Show that the maximum point of the graph of fkfk​ is (1k,1ke)(k1​,ke1​).

(c) Hence show that the maximum points of all the graphs y=fk(x)y=fk​(x) lie on a single straight line, and write down its equation.

Show the solution

(a) The GDC gives the maximum of y=xe−xy=xe−x at (1,0.368)(1,0.368) and of y=xe−2xy=xe−2x at (0.5,0.184)(0.5,0.184).

(b) Differentiate with the product rule.

fk′(x)=e−kx−kxe−kx=e−kx(1−kx)fk′​(x)=e−kx−kxe−kx=e−kx(1−kx)

Since e−kx>0e−kx>0, fk′(x)=0fk′​(x)=0 only when x=1kx=k1​. The derivative is positive for x<1kx<k1​ and negative for x>1kx>k1​, so this is a maximum.

fk(1k)=1ke−1=1kefk​(k1​)=k1​e−1=ke1​

So the maximum point is (1k,1ke)(k1​,ke1​), as given.

(c) At the maximum, x=1kx=k1​ and y=1ke=1e×1k=xey=ke1​=e1​×k1​=ex​. This relationship does not involve kk, so every maximum point lies on the line

y=xey=ex​
00.511.522.533.544.5500.20.40.60.81xy(2, 2/e)(1, 1/e)(1/2, 1/(2e))
  • k = 0.5
  • k = 1
  • k = 2
  • y = x/e
As k changes, the maximum point moves, but it always stays on the line y = x/e.

The method in part (c), eliminating the parameter between the expressions for xx and yy, is a standard Paper 3 technique. It finds the curve (here a line) on which a family of special points lies. The same idea works for points of inflexion, intercepts and vertices.

Tip

Use the GDC to test a general result on a new value of the parameter. Here, k=0.5k=0.5 predicts a maximum at (2,0.736)(2,0.736), and a quick GDC maximum search confirms it. A check like this takes seconds and catches algebraic slips.

When a part is out of reach

Paper 3 questions are designed so that very few students finish every part. The difference between a good and a weak score is usually how many marks are collected after the first difficulty, not whether the difficulty is overcome.

Keep going with given results

When a part says "show that" and prints the result, the result can be used in every later part whether or not it has been proved. Write "Using the result of part (b)…" and carry on.

Attempt the later parts

Later parts are often independent of the middle of the question, or depend only on a printed result. A part near the end that asks for a specific case or a comment can be quicker than the proof before it. Read every remaining part before deciding to leave a question.

Show partial progress

A partial proof earns marks for each correct step: the base case of an induction, a correct derivative, a correct substitution of the general term. Write down what is known and the first steps of an approach, even when the end is not in sight.

Common mistake

Spending twenty minutes on one proof and leaving the rest of the paper blank. If an inductive step will not come out after a few attempts, write the base case and the assumption (which earn marks), leave space, and move to the next part.

Communicating on Paper 3

Paper 3 answers are long, so organisation matters. Examiners need to follow the argument, and many marks are reasoning marks (R marks) for explanations, not results.

  • Use the notation the question defines, exactly. If the question calls an area AnAn​, do not rename it SS.

  • Write sentences to link steps when the reasoning is not a chain of equations: "Since e−kx>0e−kx>0 for all xx, the derivative is zero only when…".

  • Show tables of cases neatly, with the values that show the pattern.

  • When the GDC is used to explore, say what was done: "Using a GDC to graph y=f3(x)y=f3​(x), the maximum is at (0.333,0.123)(0.333,0.123)."

  • For "explain" and "justify" parts, give a mathematical reason tied to the question, not a general statement.

Exam tip

Paper 3 questions often end with an open part such as "Explain why the model is not valid for large tt" or "Suggest a reason why the result fails when k<0k<0". One clear, specific reason linked to the mathematics of the question (a negative population, a denominator equal to zero, a divergent series) earns the mark. Long general essays do not earn more.

Preparing for Paper 3

Paper 3 tests habits more than particular content, and those habits are built by practice.

  • Work through past and specimen Paper 3 questions under timed conditions, a whole question in about 30 minutes.

  • When studying any topic, ask "what happens in general?": replace numbers with a parameter and repeat the work.

  • Practise induction proofs of every kind in the course: sums, derivatives, divisibility and inequalities.

  • Practise eliminating a parameter, finding limits of sequences of results, and moving between graphs, tables and formulas.

  • After each practice question, mark it strictly and note which parts were lost through communication (a missing conclusion, an undefined letter) rather than mathematics.

Checklist

  • To do:

    I read both questions to the end during the reading time and note the printed results.

  • To do:

    I work out early cases carefully and lay them out in a table to show the pattern.

  • To do:

    I state conjectures precisely, with the domain of the variable.

  • To do:

    I can write a complete induction proof with base case, assumption, inductive step and conclusion.

  • To do:

    I can eliminate a parameter to find the curve on which a family of points lies.

  • To do:

    I use printed results in later parts even when I could not prove them.

  • To do:

    I split the time roughly equally between the two questions and move on when a part stalls.

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More IB Maths AA notes

  • Paper 2: with a GDCThe page before this.
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  • Maths AA assessmentEach Maths AA paper, the internal assessment and grade boundaries.
  • IB Maths AAThe Maths AA syllabus, how it is assessed and every notes page.

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