Augment Education
    • Question bank
    • Quick fire
    • Worksheets
    • Flashcards
    • Notes
    • Try a quick-fire round
    • All features
    • Business
    • Digital Society
    • Economics
    • Geography
    • Global Politics
    • History
    • Philosophy
    • Psychology
    • Anthropology
    • World Religions
    • Biology
    • Chemistry
    • Physics
    • Computer Science
    • Design Technology
    • ESS
    • SEHS
    • Language and literature
    • Language acquisition
    • Maths AA
    • Maths AI
    • Dance
    • Film
    • Music
    • Theatre
    • Visual Arts
    • Grade calculator
    • Grade boundaries
    • Subject checker
    • Focus timer
    • Exam countdown
    • All free tools
    • IB guide
    • All subjects
  • Blog

Search

Search subjects, the syllabus, glossary terms, the booklets, the IB guide, help and the blog

Log inStart free
augment

Augment Education

IB Diploma revision built around the syllabus.

contact@augment-education.com

Product

  • Features
  • Question bank
  • Quick fire
  • Worksheets
  • Flashcards
  • Notes
  • Subjects
  • What's new

Learn

  • IB guide
  • Booklets, explained
  • Glossary
  • Blog
  • Free tools
  • Grade calculator
  • Subject checker

Company

  • About
  • Help
  • For parents
  • For teachers
  • Comparisons

Subjects

  • English A Lit
  • English A Lang & Lit
  • Chinese A Lit
  • Chinese A Lang & Lit
  • Spanish A Lit
  • Spanish A Lang & Lit
  • English Lit & Perf
  • Spanish Lit & Perf
  • English B
  • Mandarin B
  • Spanish B
  • English ab initio
  • Mandarin ab initio
  • Spanish ab initio
  • Business
  • Digital Society
  • Economics
  • Geography
  • Global Politics
  • History
  • Philosophy
  • Psychology
  • Anthropology
  • World Religions
  • Biology
  • Chemistry
  • Physics
  • Computer Science
  • Design Technology
  • ESS
  • SEHS
  • Maths AA
  • Maths AI
  • Dance
  • Film
  • Music
  • Theatre
  • Visual Arts

Augment Education is developed independently of the International Baccalaureate Organization and is not endorsed by it. “IB” and “International Baccalaureate” are its trademarks.

© 2026 Augment Education. All rights reserved.

  • Privacy
  • Terms
  1. Subjects
  2. Maths AA
  3. Accuracy, notation and setting out

Accuracy, notation and setting out

Give answers to the right accuracy, avoid rounding too early, write notation that earns marks, and set out working so method, reasoning and follow-through marks can be awarded.

  • IB Mathematics: Analysis and Approaches
  • Exam skills
  • SL and HL

12 min readLast reviewed 14 Oct 2026

A correct method can still lose marks through the way the answer is written: a value rounded too early, a final answer to the wrong accuracy, a missing +C+C, or a "show that" argument that jumps to the result. The rules behind these marks are consistent across Papers 1, 2 and 3, and once known they are easy to follow. Most of them also make the working clearer and easier to check.

The accuracy rule

Unless a question says otherwise, every numerical answer should be given exactly or correct to three significant figures (3 s.f.). This instruction is printed on the cover of each paper, and it applies to every part of every question.

Exact answers

An exact answer is one written without rounding: 5335​, 2727​, ln⁡4ln4, π66π​, e−2e−2. On Paper 1 almost every answer is exact, because the numbers are designed for it. On Paper 2, an exact answer is needed only when the question asks for it ("find the exact value", "give your answer in the form abab​"); otherwise 3 s.f. is the usual form.

An exact answer should still be finished. Arithmetic that can be completed should be completed: 254425​​ should become 5225​, and 30.10.13​ should become 3030. A fraction that is not in its lowest terms, such as 104410​, is generally accepted as long as the numerator and denominator are integers, but simplifying it costs nothing.

Three significant figures

Significant figures count from the first non-zero digit. Three significant figures of 0.00668070.0066807 are 0.006680.00668; of 8342.268342.26 they are 83408340; of 180.252180.252 they are 180180.

Exact or unrounded value

3 s.f.

Common error

0.066807…0.066807…

0.06680.0668

0.0670.067 (2 s.f.)

11.1975…11.1975…

11.211.2

11.1911.19 (truncated, not rounded)

2.00413…2.00413…

2.002.00

22 (the zeros are significant)

8342.26…8342.26…

83408340

83428342 (4 s.f.)

1.8954…1.8954…

1.901.90

1.91.9 (2 s.f.)

An answer given to more than 3 s.f. that is correct is usually accepted unless the question specifies the accuracy, but an answer given to fewer, such as 0.0670.067, is not accurate enough and loses the accuracy mark.

Exam tip

When a question asks for a specific accuracy ("give your answer to the nearest dollar", "correct to 2 decimal places", "to the nearest degree"), a mark is attached to that accuracy. Answer in exactly the form asked for, in addition to any unrounded value in the working.

Angles, money and other contexts

The 3 s.f. rule applies to angles too, so 36.8698…°36.8698…° is 36.9°36.9°. Many students give angles in degrees to one decimal place, which for angles of 10°10° or more is at least as accurate as 3 s.f. and so is also accepted. Money is usually given to the accuracy the question asks for, often the nearest cent or the nearest whole unit. When nothing is specified, 3 s.f. still applies, although two decimal places for money is also correct and more natural.

Probabilities are given as fractions or decimals, exact or to 3 s.f. A probability of 0.0002340.000234 is written to 3 s.f., not as 0.0000.000.

Intermediate values and premature rounding

Rounding an intermediate value and then using the rounded value in later steps is called premature rounding. The error it introduces grows through the calculation and can change the final answer in the third significant figure, which loses the accuracy mark.

Worked example

A population is modelled by P(t)=200ektP(t)=200ekt, where tt is the time in years. When t=3t=3, P=350P=350.

(a) Find the value of kk.

(b) Use the model to predict the population when t=20t=20.

Show the solution

(a) Substitute t=3t=3 and P=350P=350.

350=200e3k  ⟹  e3k=1.75  ⟹  k=ln⁡1.753=0.186538…350=200e3k⟹e3k=1.75⟹k=3ln1.75​=0.186538…

So k=0.187k=0.187 (3 s.f.). Store the unrounded value in the GDC.

(b) Use the stored, unrounded value of kk.

P(20)=200e20k=8342.25…P(20)=200e20k=8342.25…

The predicted population is 83408340 (3 s.f.).

Using the rounded value k=0.187k=0.187 instead gives 200e20×0.187=8419.6200e20×0.187=8419.6, which rounds to 84208420: wrong in the third significant figure. Using k=0.19k=0.19 gives 89408940, wrong in the second.

The safe habit has two parts. Keep every intermediate value at full accuracy (stored on the GDC, or written to at least five or six significant figures), and round only the final answer. In the working, write intermediate values with an ellipsis or extra figures, such as k=0.186538…k=0.186538…, to show that the full value was used.

Common mistake

Writing an intermediate answer to 3 s.f. in part (a) and then typing that rounded value into part (b). The answer to part (a) should be written to 3 s.f. as its final answer, but part (b) must use the unrounded value. Both appear in the working: the 3 s.f. value as the answer to (a), the stored value in the calculation for (b).

Units

In context questions, give the units with every final answer: 11.211.2 m, 3.353.35 m s−1−1, 180180 cm, 0.4210.421 units22 for an area with no units given. Read the units in the question carefully: a time given in minutes, a model with tt in years, a length in centimetres with a final answer asked for in metres. A missing unit is not always penalised, but a wrong unit (or a conversion error) usually is.

Tip

Write the unit in the final sentence of each context answer: "The particle travels 11.211.2 metres in the first 55 seconds." It makes the answer clear, catches conversion errors, and answers the question in the words it was asked.

Notation that loses marks

Mathematical notation is part of the answer. Several habits look harmless but cost marks or make working unreadable.

Equals signs

An equals sign states that two things are equal. A chain such as

2x+3=11=2x=8=x=42x+3=11=2x=8=x=4

is false at almost every step, even though the student's thinking is correct. Write each equation on its own line, or connect steps with words or with ⟹⟹.

Similarly, do not write == between an expression and its derivative ("x3=3x2x3=3x2"). Write ddx(x3)=3x2dxd​(x3)=3x2 or f′(x)=3x2f′(x)=3x2.

Calculus notation

  • An indefinite integral needs +C+C: ∫2x dx=x2+C∫2xdx=x2+C. Without it the final mark is usually lost.

  • Every integral needs its dxdx (or dtdt, dydy): ∫02x2 dx∫02​x2dx, not ∫02x2∫02​x2.

  • Use f′(x)f′(x) or dydxdxdy​ consistently, and write lim⁡h→0limh→0​ in front of every line of a limit until the limit is taken.

Calculator notation

Calculator syntax is not mathematical notation. Avoid `2.5E7` (write 2.5×1072.5×107), `x^2` (write x2x2), an asterisk for multiplication (write ×× or nothing), `sqrt(5)` (write 55​), and function names such as `normalcdf` and `binompdf` (write the probability statement, such as P(X≤4)P(X≤4) with X∼B(12,0.3)X∼B(12,0.3)).

Other common slips

Written

Problem

Write instead

sin⁡x2sinx2 for (sin⁡x)2(sinx)2

Means sin⁡(x2)sin(x2)

sin⁡2xsin2x

log⁡log for natural logarithm

log⁡xlogx means base 10

ln⁡xlnx

sin⁡−1x=1sin⁡xsin−1x=sinx1​

sin⁡−1sin−1 is the inverse function

1sin⁡x=cosec⁡xsinx1​=cosecx

x=2x=2, y=5y=5 for "the coordinates"

Not in coordinate form

(2,5)(2,5)

aa for a vector

Vectors must be distinguished

a‾a​ or a⃗a by hand (aa in print)

P=1.2P=1.2

A probability cannot exceed 11

Recheck the method

x>3x>3 and x<7x<7 when asked for an interval

Not the form asked for

3<x<73<x<7 or ]3,7[]3,7[

How marks are awarded

IB markschemes use a small set of mark types. Knowing them explains why working matters so much.

Mark

Stands for

Awarded for

M

Method

An attempt at a correct method, such as substituting into the right formula or setting a derivative to zero.

A

Answer (accuracy)

A correct answer or a correct intermediate value. A marks usually depend on the M mark before them.

R

Reasoning

A clear reason or justification, such as a sign test, a conclusion to an induction proof, or a reason for rejecting a solution.

AG

Answer given

Marks the point where a "show that" result is reached. No marks are awarded for writing it.

FT

Follow through

Marks awarded for correct work that uses an earlier wrong answer.

A mark written in brackets, such as (M1) or (A1), can be implied by later correct work. If a correct final answer appears without the step, the bracketed mark is still given. Marks without brackets, such as M1, are awarded only when the method is seen, so a correct answer with no working may not earn them.

A marked solution

The following short question shows how marks attach to lines of working.

Worked example

Find the coordinates of the vertex of the parabola y=2x2−12x+5y=2x2−12x+5.

Show the solution

Working

Mark

x=−b2a=124x=−2ab​=412​

(M1)

x=3x=3

(A1)

y=2(3)2−12(3)+5y=2(3)2−12(3)+5

(M1)

vertex (3,−13)(3,−13)

A1

A student who writes only (3,−13)(3,−13) earns all four marks here, because the bracketed marks are implied. A student who writes x=3x=3 and then makes an arithmetic slip in yy earns three of the four. A student who writes only (3,−11)(3,−11) earns nothing, because there is no working to award.

The last case is the strongest argument for showing working. A short line of method protects most of the marks against a single slip.

Follow-through

If an answer to one part is wrong and the wrong value is then used correctly in a later part, the later part can earn its marks, marked FT. The error is penalised once, where it happens.

For example, a question asks (a) find f′(x)f′(x) for f(x)=x3−6xf(x)=x3−6x, and (b) find the gradient of the curve at x=2x=2. A student who writes f′(x)=3x2−6xf′(x)=3x2−6x in part (a) loses marks there. In part (b), the student substitutes correctly: f′(2)=3(4)−12=0f′(2)=3(4)−12=0. The correct gradient is 66, but part (b) still earns full follow-through marks, because the method in (b) is correct for the derivative the student found.

Follow-through has limits. It is usually not awarded when the earlier error makes a later part much simpler (for example, a wrong derivative that turns a quadratic equation into a linear one), or when the follow-through answer is clearly impossible, such as a negative length or a probability greater than 11, and no comment is made. Follow-through can only be awarded when the working is visible.

Exam tip

Never abandon a later part because an earlier answer might be wrong. Use the value you have, show the method clearly, and the follow-through marks are available. If an earlier answer is obviously impossible, say so briefly in the working ("this probability is greater than 1, so an earlier error is likely").

A related rule covers misreading. If a value is copied from the question incorrectly and then used correctly, a small penalty is usually applied once and the rest of the work can be marked as if the copied value were correct, provided the question has not become easier.

Setting out a "show that"

A "show that" question prints the answer, so every mark is for the steps. Examiners look for a clear logical route from the given information to the printed result.

  1. Start from what is given, or from one side of the result.

  2. Write every algebraic step on its own line, including steps that seem obvious.

  3. Do not work backwards from the result, and do not manipulate both sides of an identity at once.

  4. End with the printed result, written exactly as it appears, and a short statement that it has been reached.

Worked example

Show that the equation (k+1)x2−4x+(k−2)=0(k+1)x2−4x+(k−2)=0 has real roots if k2−k−6≤0k2−k−6≤0.

Show the solution

A quadratic equation has real roots when its discriminant is non-negative.

Δ=(−4)2−4(k+1)(k−2)Δ=(−4)2−4(k+1)(k−2)

Expand the product, then simplify.

Δ=16−4(k2−k−2)=16−4k2+4k+8=24+4k−4k2Δ=16−4(k2−k−2)=16−4k2+4k+8=24+4k−4k2

For real roots, Δ≥0Δ≥0.

24+4k−4k2≥024+4k−4k2≥0

Divide by −4−4, which reverses the inequality.

k2−k−6≤0k2−k−6≤0

This is the given condition. (For this to be a quadratic, k≠−1k=−1.)

In a markscheme, the last line carries AG: it earns nothing by itself. The marks are for the discriminant, the expansion and the inequality direction.

Common mistake

Starting from k2−k−6≤0k2−k−6≤0 and working back to Δ≥0Δ≥0, or writing the discriminant and then jumping straight to the printed inequality. Both skip the reasoning that the marks are for. Work forwards, and include the step where the inequality is reversed.

The final line matters

In a "show that", the printed result must actually appear at the end of the working. A student who reaches 24+4k−4k2≥024+4k−4k2≥0 and stops has not finished, even though the result follows. Write the final step and the result.

Presentation on the page

  • Number every part clearly: (a), (b)(i), (b)(ii). In Section B and Paper 3, start each question on a new page.

  • Cross out errors with a single line instead of erasing them. Crossed-out work is not marked if a replacement is given, so do not leave two different answers to one part: the examiner may mark the first one, or the worse one.

  • Write the final answer clearly, often as a sentence or underlined, so it is not mistaken for an intermediate value.

  • Draw diagrams in pencil, label everything, and keep them large enough to read.

  • Keep working near the question it belongs to. Work for one question written in the space for another may be missed.

Checklist

  • To do:

    I give every answer exactly or to 3 s.f., unless the question asks for something else.

  • To do:

    I keep intermediate values unrounded and round only the final answer.

  • To do:

    I give units with context answers and answer in the words of the question.

  • To do:

    I write +C+C, dxdx, coordinates in brackets and probability statements correctly.

  • To do:

    I never write calculator syntax as working.

  • To do:

    I understand M, A, R, AG and FT marks and show the working they need.

  • To do:

    I set out "show that" proofs forwards, step by step, ending with the given result.

Keep your place

In Augment the notes remember where you stopped and which pages you have finished.

Open in Augment

More IB Maths AA notes

  • Using the GDCThe page before this.
  • The mathematical explorationThe next page.
  • Maths AA assessmentEach Maths AA paper, the internal assessment and grade boundaries.
  • IB Maths AAThe Maths AA syllabus, how it is assessed and every notes page.

Carry on with Maths AA in Augment

With a free account, Augment remembers where you stopped in the notes and which questions you have marked.

Start free