Fit quadratic, cubic, exponential, power and sine regression curves with technology, measure their fit with residuals, the sum of square residuals and R², and choose between models using context as well as R².
Each is in the Maths AI glossary, with every other term in the subject.
A measure of how well a regression model fits bivariate data, equal to the proportion of the variation in the dependent variable that is explained by the model; it lies between 0 and 1 for a least squares model, with values close to 1 showing a close fit.
Fitting a model of the form
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Fitting a model of the form , or equivalently , to bivariate data with positive -values by least squares.
The curve of a chosen family (such as quadratic or exponential) whose parameter values make the sum of square residuals for the data as small as possible.
The process of fitting a curve that is not a straight line, such as a quadratic, cubic, exponential, power or sine function, to bivariate data by choosing the values of its parameters that give the closest fit.
Fitting a model of the form to bivariate data with positive - and -values by least squares.
Fitting a model of the form to bivariate data by least squares.
The difference between an observed value of the dependent variable and the value predicted by a model, ; it is positive when the data point lies above the model's graph and negative when it lies below.
A scatter diagram of the residuals of a model, , plotted against the independent variable ; residuals scattered randomly about zero suggest a suitable model, while a curved or other systematic pattern shows that the model's form is wrong.
Fitting a model of the form to bivariate data by least squares, where is the amplitude, the period (with in radians) and the principal axis.
The sum of the squares of the residuals of a model, ; it measures the total squared error of the model, and a smaller value means a closer fit to the same data.
Find the equation of a least squares regression curve (quadratic, cubic, exponential, power or sine) using technology, written in the variables of the context.
Calculate residuals and the sum of square residuals for a given model.
Compare two models fitted to the same data using .
Write down the coefficient of determination from technology and interpret it as the proportion of the variation in the dependent variable explained by the model.
Explain the connection for a linear model, and compare for a curve with for a regression line.
Use a model to make predictions, and comment on their reliability, including extrapolation.
Justify the choice of model using the context, the shape of the data and the residuals, explaining why alone is not enough.
Many relationships in science, economics and everyday life are curved. Stopping distance grows faster than speed, air pressure falls by a constant factor for each kilometre of height, and the area of Arctic sea ice rises and falls with the seasons. A regression line cannot describe any of these well. Non-linear regression extends the least squares idea of subtopic 4.4 from straight lines to curves, so that the best curve of a chosen type can be found for any data set.
Fitting a curve with technology takes seconds. The mathematics lies in choosing which type of curve to fit, measuring how well it fits, and deciding whether a better-fitting curve is actually a better model. Two measures of fit are used for the second task: the sum of square residuals, which measures the total size of the errors, and the coefficient of determination , which measures the proportion of the variation in the data that the model explains.
YouTubeA mathematical model chosen to describe data has a fixed form, such as , and parameters , ,
The six families of model in the course are summarised in the table. Each family has its own shape, and the shape of the scatter diagram together with what is known about the context decides which families are worth trying.
Model | Equation | Shape and typical use |
|---|---|---|
Linear | constant rate of change | |
Quadratic |
Regression models found with the GDC. The letters are the model's parameters.
A quadratic model has one turning point and changes gradient at a constant rate. It suits quantities that rise and then fall (the height of a thrown ball, the profit at different prices) or that grow increasingly fast from a starting value, such as stopping distance.
A cubic model can have two turning points and a point of inflexion, which lets it follow an S-shaped or wave-shaped pattern over a limited range. It is used for cross-sections of rivers and roads, volumes and the shapes of objects.
Polynomial models become unreliable quickly outside the data. Every quadratic and cubic eventually heads towards or , so predictions beyond the data range can become negative, enormous or turn in the wrong direction even when the fit inside the range is excellent.
The depth of a river is measured at 2 m intervals across its width, from one bank to the other.
Distance from bank (m) | 0 | 2 | 4 | 6 | 8 | 10 | 12 |
|---|---|---|---|---|---|---|---|
Depth (m) | 0 | 1.1 | 2.6 | 3.4 | 3.1 | 1.8 | 0.2 |
Depths across a river (hypothetical data).
An exponential model describes a quantity that changes by the same percentage in each equal step of , the continuous version of a geometric sequence from subtopic 1.3. It is the natural model for exponential growth and exponential decay.
The two forms are the same model. Since , the constants are linked by
Many GDCs give . When the form is needed, take
A power model passes through the origin when , and describes quantities in which multiplying by a factor multiplies by a fixed factor: doubling
The value of often has a meaning. For a pendulum, physics predicts that the period is proportional to the square root of the length, so power regression on measured data should give . A value close to the predicted exponent is evidence that the theory fits.
A sinusoidal model describes a quantity that repeats in a regular cycle. Sine regression fits all four parameters at once.
The GDC must be in radian mode for sine regression, and the period of the fitted model is . Sine regression needs data covering at least one full cycle, and some GDCs accept an estimate of the period, which helps the calculation settle on a sensible answer.
A model is chosen for reasons, and the reasons come in a definite order.
The context. Physical laws, growth processes and cycles suggest a family before any data are seen: populations with unlimited resources grow exponentially, seasonal quantities repeat every 12 months, braking distance depends on the square of speed.
The scatter diagram. The shape of the data (curving up or down, one or two turning points, a repeating pattern, levelling off) rules families in or out.
Behaviour outside the data. A model used for prediction must behave sensibly beyond the observed range: an exponential model of a population eventually exceeds any limit, a quadratic for a falling object eventually rises again.
The measures of fit, and , compare the candidates that survive the first three tests.
Every model gives a predicted value (read "y-hat") for each data value . The difference between what was observed and what was predicted measures how far that point is from the model.
The diagram of residuals shows them as vertical segments between each data point and the model curve. They are vertical because the model is used to predict from , so its errors are errors in .

Adding the residuals does not measure the total error, because positive and negative residuals cancel: a curve that misses badly above and below can have residuals adding to zero. Squaring each residual makes every term positive and gives large misses more weight than small ones, for the same reasons as in the least squares line of subtopic 4.4.
is zero only when the model passes through every point. Its units are the square of the units of , so it can be used to compare different models fitted to the same data, but not to compare models of different data sets: a data set measured in metres and the same data in centimetres have values of
Within one family of curves, different parameter values give different values of . The best curve of that family is the one with the smallest.
The least squares regression line of subtopic 4.4 is the special case for the linear family. For every family in the course, the GDC finds the parameters numerically. The least squares principle also gives a way to judge any model: a model chosen by some other method (from two data points, from a theory, from a graph drawn by eye) always has an at least as large as the least squares curve of its family, and comparing the two shows how much better the fit could be.
Models are often proposed with stated parameters, from theory or from a few data points, and two such models can be compared on the same data. The method is the same every time.
Use the model to calculate the predicted value at each data value .
Find each residual
On the GDC, the lists do the work: enter the -values in L1 and the -values in L2, define L3 as the model applied to L1 (for example ), define L4 as
(hours) | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
(thousands) | 52 | 80 | 115 | 170 | 260 |
Bacteria counts in a culture (hypothetical data).
The method is the same for any data set: the model with the smaller on the same data fits better. The exponential regression on these counts gives , whose sum of square residuals is about 21.6, so even Model A is far from the best exponential fit.
All the least squares curves in the course come from the GDC's statistics menu. The procedure is the same for every family; only the regression type changes.
Enter the independent variable in one list and the dependent variable in another.
Draw a scatter diagram to see the shape.
Choose the regression type: on a TI-84 Plus CE, STAT → CALC → QuadReg, CubicReg, ExpReg, PwrReg or SinReg; on a Casio fx-CG50, MENU → Statistics → CALC → REG, then the type (X^2, X^3, Exp, Pwr, Sin).
Read the parameters and, where shown, . On a TI-84 Plus CE, appears only if DiagnosticOn (or STAT DIAGNOSTICS set to on) has been selected.
Store the equation in the graphing menu so that later predictions use the full values.
On paper, write the equation in the variables of the question with coefficients to 3 significant figures, the value of if asked, and the predictions made from the stored equation.
The U.S. Standard Atmosphere is a reference model of the atmosphere used in aviation and engineering. It lists the air pressure at the base of each layer of the atmosphere.
Height (km) | 0 | 11 | 20 | 32 | 47 |
|---|---|---|---|---|---|
Pressure (kPa) | 101.325 | 22.6321 | 5.47489 | 0.868019 | 0.110906 |
Source: U.S. Standard Atmosphere, 1976, layer base pressures (geopotential height), via Wikipedia "U.S. Standard Atmosphere".
The graph of the exponential model through the atmosphere data shows how closely the curve follows all five points, from sea level to 47 km.
The model is not perfect. It predicts 104.3 kPa at sea level against the true 101.3 kPa, and 20.8 kPa at 11 km against 22.6 kPa. The real atmosphere is not one exponential: the rate of fall depends on temperature, which changes from layer to layer, and the Standard Atmosphere itself uses a different formula in each layer. Over the whole range, a single exponential is an excellent summary; for accurate values at a particular height, the layered model is needed.
Sometimes a model is not one of the GDC's types as it stands, but a rearrangement turns it into one. A hot drink cooling in a room at 20 °C follows Newton's law of cooling, , which has a constant added to the exponential. Subtracting the room temperature gives
(minutes) | 0 | 5 | 10 | 15 | 20 | 25 |
|---|---|---|---|---|---|---|
(°C) | 88 | 71 | 59 | 49 | 42 | 37 |
Temperature of a cup of coffee in a room at 22 °C (hypothetical data).
The cooling example shows why the constant matters. Exponential regression on itself would give a curve heading towards 0 °C, which is impossible in a room at 22 °C.
A class times the swings of a pendulum for six lengths. Physics predicts that the period of a pendulum of length is
Length (m) | 0.2 | 0.4 | 0.6 | 0.8 | 1.0 | 1.2 |
|---|---|---|---|---|---|---|
Period (s) | 0.90 | 1.27 | 1.55 | 1.80 | 2.00 | 2.20 |
Periods of a pendulum timed by a class (hypothetical data).
The area of the Arctic Ocean covered by sea ice grows through the winter and shrinks through the summer. The National Snow and Ice Data Center publishes the monthly average extent, the area of ocean with at least 15% ice cover.
Month | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
Extent (million km²) | 13.36 | 14.19 | 14.43 | 13.92 | 12.82 | 10.99 | 8.21 | 5.51 | 4.38 | 6.41 | 9.68 | 11.98 |
Source: National Snow and Ice Data Center, Sea Ice Index version 4, Northern Hemisphere monthly extent, 2023 (month 1 = January).
Sine regression on the GDC in radian mode gives
with . The graph of the sine model through the 2023 data shows the yearly cycle and where the model departs from it.
Each parameter has a meaning in context.
Amplitude : the extent varies about 4.87 million km² above and below its average.
Principal axis : the average extent over the year is about 10.4 million km².
Period
The fitted period of 11.3 months is a warning sign. The true cycle is exactly one year, and the regression has shortened the period to bend the curve closer to the steep autumn recovery. The real cycle is not symmetric: the ice melts slowly from March to September and then refreezes quickly, which a sine curve cannot reproduce. Fixing the period at 12 months () gives a slightly lower of 0.949 but a model that can be used for several years in a row, which the 11.3-month model cannot.
The sum of square residuals depends on the units and on the amount of data, so on its own it does not show whether a fit is good. An of 92 for stopping distances in metres and one of 12 for pressures in kilopascals cannot be compared. A measure of fit on a fixed scale is needed.
Without any model, the best single prediction of is its mean . The total squared error of that prediction measures how much the -values vary.
A model that uses reduces this error to . The fraction of the variation that the model removes, or "explains", is
Two extreme cases show what measures. If the model passes through every point, and
YouTubeIn practice comes from the GDC, as part of the regression output. The formula is useful for understanding what the number means and why it lies between 0 and 1, and for calculating for a model that the GDC did not fit.
For a straight line found by least squares, the coefficient of determination equals the square of Pearson's product-moment correlation coefficient:
This is why the GDC shows beside for linear regression. It also explains the scale of : a correlation of , which sounds strong, means that the line explains only
To compare a linear model described by with a curve described by , the two numbers are first put on the same scale by squaring or taking the square root of . The comparison then names both values, such as "
A higher means a closer fit to the data, which is only one of the qualities of a good model. Three facts limit what can decide.
More parameters never lower . Every straight line is a quadratic with , so the best quadratic fits at least as well as the best line; every quadratic is a cubic with zero cubic term, and so on. With 6 data points a polynomial of degree 5 passes through every point and gives , while making absurd predictions between and beyond the points.
Many factors besides affect the validity of a model: whether its form matches the process in the context, whether its parameters have sensible values, whether its residuals show a pattern, and how it behaves beyond the data.
A plot of the residuals against shows whether a model has captured the shape of the data.
If the model has the right form, what is left over should be random noise: residuals above and below zero in no particular order. If the residuals follow a curve, the model has missed part of the pattern, and a different family should be tried. A residual plot is an optional check, and the clearest way to see why one model is better than another.
The UK Highway Code gives typical total stopping distances for cars on a dry road at six speeds. The stopping distance is the distance travelled while the driver reacts (thinking distance) plus the distance travelled while braking.
Speed (mph) | 20 | 30 | 40 | 50 | 60 | 70 |
|---|---|---|---|---|---|---|
Stopping distance (m) | 12 | 23 | 36 | 53 | 73 | 96 |
Source: The Highway Code (UK), Rule 126, typical stopping distances, via Wikipedia "Braking distance".
Linear regression gives with , so
The residual plots of the two models make the difference sharper. The linear model's residuals form a U shape: positive at 20 and 70 mph, negative in between. The line is too low at the ends and too high in the middle because the data curve upwards. The quadratic model's residuals are all within 0.4 m of zero with no pattern.

The context gives the decisive reason. Subtopic 5.13, Kinematics, shows that thinking distance is proportional to speed and braking distance to the square of speed, so the stopping distance should have the form , a quadratic with no constant term. Quadratic regression is free to fit any constant term, and the fitted value is only 0.6 m, very close to zero, which supports the quadratic family. The linear model also fails the common-sense test: at it predicts a stopping distance of −26.6 m.
A cubic model gives , slightly higher than the quadratic, as it must be. Its cubic coefficient is tiny () and has no physical meaning, and the extra parameter only follows the rounding of the published distances to whole metres. The quadratic is the better model despite its very slightly lower
Predicting beyond the data shows how much the choice matters. At 80 mph, above the UK motorway speed limit of 70 mph, the linear model predicts 108 m and the quadratic 122 m. A driver relying on the linear model would underestimate the distance needed to stop by about 14 m.
Non-linear regression appears in Paper 2 and Paper 3 modelling questions, usually in parts worth 1–3 marks, and occasionally as a Paper 1 question on . Typical parts ask you to find the equation of a least squares regression curve (an attempt at the right type of regression earns a method mark; the equation in context variables with coefficients to 3 s.f. earns the answer mark), write down , interpret
(weeks) | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
|---|---|---|---|---|---|---|---|---|
(thousands) | 2.1 | 2.8 | 3.9 | 5.1 | 7.0 | 9.2 | 12.8 | 16.6 |
Users of a new app (hypothetical data).
The doubling time in part (d) comes from the model, not from the table: the users rise from 2.1 to 3.9 thousand by week 3, but the data points do not lie exactly on the curve, so reading a doubling time from them gives a different and less reliable answer.
A model predicts . Find the residual for the data point . [2]
The value of an investment is modelled by . Observed values are , 110, 95, 89 at
The height m of a ball seconds after it is thrown is recorded: , ,
A bowl of soup cools in a room at 20 °C. Its temperature °C is 85, 68, 56, 47, 40, 35 at , 5, 10, 15, 20, 25 minutes. The model is proposed. (a) Find the least squares exponential regression equation for
A ball rolls down a ramp. The distance cm after seconds is 0.6, 2.3, 5.2, 9.1, 14.4, 20.5 at , 1, 1.5, 2, 2.5, 3. (a) Find the equation of the least squares power regression curve. [2] (b) Comment on the value of the exponent in the context of motion with constant acceleration, where
For the data , , , ,
A student fits linear, quadratic and cubic models to the same 7 data points and chooses the cubic because it has the highest . Comment on the validity of this decision. [2]
The mean monthly temperature °C in a city (hypothetical) in months to 12 is 4, 5, 8, 12, 16, 19, 21, 21, 17, 13, 8, 5. (a) Find the equation of the sine regression curve . [2] (b)
; residual
Non-linear regression fits a curve of a chosen family (quadratic, cubic, exponential, power, sine) by least squares, using technology.
A residual is , the vertical distance (with sign) from a data point to the model.
I can choose which regression families to try from the context and the scatter diagram.
I can find quadratic, cubic, exponential, power and sine regression equations on my GDC.
I can write a regression equation in the question's variables with coefficients to 3 s.f.
I can convert between and
53 exam-style questions on this subtopic, written in the style of the IB papers. The first has its markscheme open. Counted on
Dr Okafor grows a bacterial culture in a petri dish. She measures the number of bacteria, thousand, hours after the start of the experiment.
(hours) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 |
|---|---|---|---|---|---|---|---|---|
(thousands) | 2.1 | 5.8 | 14.2 | 27.6 | 39.5 | 46.0 | 48.7 | 49.9 |
Dr Okafor first fits an exponential model, , to the data for only. Use exponential regression on these four data points to find the value of and the value of
Ana pours a cup of tea in a room where the temperature is a constant 21 °C. She records the temperature of the tea, °C, minutes later.
(minutes) | 0 | 2 | 4 | 6 | 8 | 10 | 15 | 20 |
|---|---|---|---|---|---|---|---|---|
(°C) | 88 | 79.5 | 72.0 | 65.6 |
A forester, Mateus, measures the mean height, metres, of eucalyptus trees of age years in a plantation.
(years) | 2 | 4 | 6 | 8 | 12 | 16 | 20 | 25 |
|---|---|---|---|---|---|---|---|---|
(m) | 3.4 | 8.1 | 11.5 | 13.3 | 16.9 | 18.6 |
one turning point; projectiles, areas, stopping distances |
Cubic | up to two turning points; volumes, cross-sections |
Exponential | or | constant percentage change; growth, decay, cooling |
Power | passes through the origin; scaling laws in physics and biology |
Sine | repeating cycles; seasons, tides, daylight |
(a) Cubic regression with in L1 and in L2 gives , , , (M1)
A1
(b) (0.976141…) A1
(c) Substituting into the stored equation: m (2.930357…) (M1)A1
(d) Using the GDC's maximum function on the graph for : (M1)
the maximum depth is m at m A1
The deepest measured value is 3.4 m at , so the model underestimates the greatest depth by about 0.2 m. R1
(e) m is beyond the far bank (outside the data range); the model gives m, a negative depth, which is impossible. R1
Square each residual and add.
Determine which model fits the data better, using the sum of square residuals. [6]
Model A predicts : 50, 75, 112.5, 168.75, 253.125. (A1)
(M1)A1
Model B predicts : 55, 79.75, 115.6375, 167.674…, 243.128…. (A1)
A1
Model A has the smaller sum of square residuals (84.1 compared with 300), so Model A fits the data better. A1
Most of Model B's error comes from , where it predicts 243 thousand against 260 thousand observed: its growth factor of 1.45 is too small for the later counts.
(c) Write the model in the form . [2]
(d) Find the increase in height over which the pressure predicted by the model halves. [2]
(a) Exponential regression with in L1 and in L2 gives and (M1)
A1
(b) (0.999316…) A1. About 99.9% of the variation in is explained by the model, so an exponential model describes the fall in pressure with height extremely well. R1
(c) (M1)
A1
(d) The pressure halves each time increases by where :
(M1)A1
The model's pressure halves about every 4.7 km of height, whatever the starting height.
(b) Find the least squares exponential regression equation for in terms of . [3]
(c) Hence estimate the temperature of the coffee after 40 minutes, and comment on the reliability of this estimate. [3]
(a) Rearranging the model gives , which is an exponential function of . R1
(b) Enter in L1 and in L2: 66, 49, 37, 27, 20, 15. (A1)
Exponential regression gives , (M1)
A1
(c) °C (3 s.f.) (M1)A1
This is extrapolation, 15 minutes beyond the last reading, so it is less reliable than a value inside the data range; however, the model approaches the room temperature of 22 °C, which is physically sensible, so the estimate is reasonable. R1
A1
(b) The exponent 0.498 is very close to the theoretical 0.5 and the coefficient 2.01 is very close to 2.006, R1 so the data strongly support the theory that the period is proportional to the square root of the length. A1
(c) s (3 s.f.) (M1)A1
This is a short extrapolation beyond 1.2 m, but the model is supported by theory as well as by the data, so it can be trusted more than a model with no physical basis.
Maximum and minimum: the model's maximum, , occurs at (March) and its minimum, , at (between August and September).
(a) Calculate for the model. [2]
(b) Interpret the value in context. [1]
(a) (M1)
A1
(b) 92% of the variation in the test scores is explained by the quadratic model in hours of revision. R1
describes the fit inside the data range only. Two models with almost equal can give completely different predictions outside the data range, which is where the dangers of extrapolation lie.
does not show causation or correctness. A high shows that the curve follows the data; it gives no evidence that causes or that the model's form is the true one (subtopic 4.4, causation).
(ii) Write down the value of for this model, correct to 4 significant figures. [3]
(c) Hence compare the suitability of the two models. [2]
(d) Use the exponential model to find the time it takes for the number of users to double. [2]
(e) Use the exponential model to predict the number of users at the end of week 12, and comment on the reliability of this prediction. [3]
(f) By considering large values of , write down one criticism of the exponential model. [1]
A colleague suggests the model .
(g) Find the sum of square residuals for the colleague's model. [2]
(h) The sum of square residuals for the model in (b) is 0.174. Comment on the colleague's model. [1]
(a) (i) (2.01547…, −1.63214…) A1A1
Note: award at most A1A0 if the answer is not an equation, or uses and .
(ii) (0.962982…) A1
(b) (i) attempt at exponential regression (M1)
(1.56584…, 1.34605…) A1
Note: accept .
(ii) (0.999547…) A1
(c) comparing with (or with ):
the exponential model is more suitable (explains a greater proportion of the variation in ) A1
Note: award M0A0 for "the exponential model has better correlation" without values.
(d) or
weeks A1
Note: do not award marks for a doubling time read from the data in the table.
(e) thousand (55,400 users) (M1)A1
week 12 is outside the range of the data (extrapolation), so the prediction may be unreliable R1
(f) the model predicts that the number of users grows without limit (eventually exceeding the population) R1
(g) predicted values 2.04, 2.7744, 3.773…, 5.131…, 6.978…, 9.491…, 12.908…, 17.555… (M1)
(1.03047…) A1
(h) the colleague's (1.03) is about six times the least squares value (0.174), so the colleague's model fits the data less well R1
Total [17]
Predicted 120, 108, 97.2, 87.48; residuals −2, 2, −2.2, 1.52; (15.1504).
(a) . (b) (0.999865). (c) Vertex at : m.
(a) (, ). (b) °C.
(a) . (b) The exponent 1.97 is close to 2, consistent with constant acceleration. (c) cm; extrapolation beyond 3 s, and the ramp may end, so less reliable.
(a) . (b) . (c) : the quadratic explains far more of the variation in and fits the curved data much better.
Not valid: a model with more parameters always has at least as high, so cannot fairly compare models with different numbers of parameters; the choice should also use the context, residuals and behaviour outside the data.
(a) (radian mode). (b) months, close to the expected 12 months of a yearly cycle. (c) 8.54 °C: the temperature varies about 8.5 °C above and below the yearly average of about 12.5 °C.
Write regression equations in the context's variables with coefficients to 3 s.f., and use stored values for predictions; and are linked by .
For sine regression use radian mode; the period is , the amplitude and the principal axis .
is the proportion of the variation in explained by the model; , from 0 (no better than the mean) to 1 (a perfect fit).
For the least squares line ; compare a curve's with a line's , quoting both values.
alone does not choose a model: more parameters never lower it, it says nothing about behaviour outside the data, and it does not show causation; the context, the residual pattern and extrapolation behaviour must also be considered.
I can use a rearrangement, such as , to fit a model that is not directly a GDC type.
I can find the period, amplitude and principal axis of a sine regression model and interpret them.
I can calculate residuals and for a given model, by hand or with lists.
I can use to decide which of two models fits the same data better.
I can write down from my GDC and interpret it as a proportion of variation explained.
I can explain why for a regression line and compare with correctly.
I can explain why a higher does not always mean a better model.
I can recognise a pattern in residuals that shows a model has the wrong form.
I can use a model to predict, find a doubling time or half-life, and comment on extrapolation.
3 marks
evidence of exponential regression on the first four points (M1)
⇒ A1
⇒ A1
[3 marks]
Use this exponential model to predict the number of bacteria when . Hence comment on the suitability of the exponential model for .
3 marks
(M1)
⇒ (thousand) A1
much larger than the observed thousand, so the exponential model is not suitable (the growth slows down as the dish fills) R1
[3 marks]
She then fits a logistic model of the form to all the data. Use logistic regression to find the value of , of and of .
3 marks
⇒ A1
⇒ A1
Interpret the value of in the context of the experiment.
1 mark
the maximum number of bacteria (about ) that the petri dish can support (carrying capacity) A1
[1 mark]
Use the logistic model to find the time at which the number of bacteria first reaches 45 thousand.
2 marks
(M1)
⇒ (hours) A1
[2 marks]
Find the time at which, according to the logistic model, the number of bacteria is increasing most rapidly, and the rate of increase at that time.
3 marks
OR maximum of OR (M1)
⇒ (hours) A1
(thousand per hour) (
[3 marks]
55.4 |
46.2 |
39.5 |
Ana believes that the temperature of the tea will approach the temperature of the room.
Let . Use exponential regression to find a model of the form .
3 marks
Hence write the model in the form , giving the value of .
2 marks
Find the time taken for the difference between the temperature of the tea and the temperature of the room to halve.
2 marks
Ana drinks her tea once its temperature falls below 60 °C. Use the model to find the time at which she starts to drink it.
2 marks
Ana's friend Bruno fits an exponential model directly to the values of and obtains .
Find the temperature that Bruno's model predicts after 2 hours.
2 marks
Hence explain why Ana's model is more appropriate for large values of .
1 mark
20.9
22.0 |
Mateus models the data using .
Use natural logarithmic regression to find the value of and the value of .
3 marks
Write down the value of the coefficient of determination, , and interpret its value.
2 marks
Use the model to estimate the mean height of 10-year-old trees.
2 marks
The trees are harvested when their mean height reaches 25 m. Use the model to find the age at which the trees are harvested.
2 marks
State one limitation of Mateus's model for very old trees.
1 mark
Mateus's colleague, Ifeoma, suggests a logistic model . Her model passes through the points
Find the mean height of 50-year-old trees predicted by each model. Hence suggest which model is more suitable for old trees.
3 marks
Note: Accept values that differ slightly in the third significant figure because of the GDC algorithm.
[3 marks]
4 marks