Derive and use the compound angle identities for sin, cos and tan and the double angle identity for tan to find exact values, prove identities, solve equations and write a cos θ + b sin θ as a single wave.
Each is in the Maths AA glossary, with every other term in the subject.
An identity that writes a trigonometric function of a sum or difference of two angles, such as , in terms of the sines, cosines or tangents of and separately.
The single-wave form
With a free account, Augment remembers where you stopped and what you have practiced.
A compound angle is an angle written as a sum or difference of two others, such as or . The compound angle identities give the sine, cosine and tangent of such an angle from the sines, cosines and tangents of the separate parts. They produce exact values for angles such as
The same identities explain why two waves of the same frequency always add up to a single wave of that frequency. A combination such as is one cosine wave with amplitude , shifted sideways. This fact is used wherever oscillations combine, from sound and alternating current to tides.
A function that satisfies for all inputs is called linear, and sine is not one. Taking
Since , the sine of a sum is not the sum of the sines. The correct rule involves both sines and cosines of the two angles.
The six compound angle identities are usually written in three lines, with the upper sign of and going together and the lower signs going together.
Written out in full, the six identities are:
Sum | Difference |
|---|---|
The sine identities keep the sign of the compound angle and mix the functions (sin cos, then cos sin). The cosine identities reverse the sign and keep the functions together (cos cos, then sin sin).
All six identities follow from one of them, , which can be proved on the unit circle. Take the points

First, find with the distance formula:
Now rotate the triangle about through the angle . The point moves to and
Setting the two expressions equal and cancelling gives
The argument uses only coordinates on the unit circle, so it holds for all angles and , not only acute ones. The cosine rule in triangle gives the same result for when the triangle exists.
The remaining identities follow from the first by replacing angles and using the symmetry of the graphs. Cosine is an even function and sine is an odd function, so and .
Cosine of a sum. Replace with :
Sine of a sum. Use and
Sine of a difference. Replace with in step 2:
Tangent of a difference. Replace with , using .
Euler's formula from 1.13 gives the sum identities in a few lines. By the laws of exponents,
Two complex numbers are equal only when their real parts are equal and their imaginary parts are equal. The real parts give and the imaginary parts give . This is an example of equivalence between representations: the same fact about angles appears as a property of rotation in the plane and as a law of exponents.
Angles such as , and are sums or differences of
Some angles can be split in more than one way, for example or
When the ratios of and are given instead of the angles themselves, find the missing sine or cosine of each angle first, with the sign fixed by its quadrant, then substitute.
An expression that has the shape of the right-hand side of an identity can be collapsed into a single function. This is often the quickest route to an exact value.
Setting in the sum identities gives the double angle identities. The ones for sine and cosine are studied in 3.6; here they appear as special cases.
The same substitution in the tangent identity gives a new result.
Applying the identities twice gives the trigonometric functions of and other multiples in terms of . The method is to write the multiple as a sum, for example , and expand.
To prove an identity that contains a compound angle, expand it with the appropriate identity first. Then simplify, aiming at the form on the other side. The target suggests the route: if it contains only , divide by a product of cosines; if it contains only and of single angles, expand and collect like terms.
Results such as this one turn a sum of two sines into a product, which is useful in integration (5.16) and in physics, where two notes of slightly different frequencies produce beats.
When one of the angles is a standard angle, substitute its exact values as soon as the identity has been expanded.
An equation that contains a compound angle with a known part, such as , is usually solved by expanding, collecting the terms and the
The same method gives exact answers even when the tangent is not a familiar value, provided it matches a compound angle found earlier.
The tangent identity turns an equation in into an equation in alone, often a quadratic.
The graph of looks exactly like a cosine curve: it has the same period, , but a larger amplitude and a horizontal shift. The compound angle identity explains why. For ,
This equals for all if the coefficients match:
Squaring and adding gives
The harmonic form shows at once that has maximum value , when , and minimum value
The values of and fix the quadrant of , so check their signs before using .
Any two oscillations of the same period combine into one oscillation of that period. If two sound waves of the same frequency reach a microphone, contributing pressures and

I can state the compound angle identities for , and
36 exam-style questions on this subtopic, written in the style of the IB papers. The first has its markscheme open. Counted on
Consider the angle radians.
By writing as , find the exact value of .
3 marks
Find the exact value of , giving your answer in the form
It is given that , where
It is given that , where
One of 33 short multiple-choice questions on 3.10. Pick an answer to see why it's right or wrong.
For , what is the solution of ?
The entries of the mathematics: analysis and approaches formula booklet that 3.10 uses. Each opens in the explained booklet.
Tangent of a sum. Divide by , then divide the numerator and the denominator by :
(a) Write :
(b) Write
The answer is negative, as it should be for an angle in the second quadrant.
(c) Write and use
Rationalise by multiplying the numerator and the denominator by :
Check with a calculator:
Find the missing ratios. is acute, so :
is obtuse, so :
(a)
(b)
(c) and
Check:
(a) This is with and :
(b) This is with and
(c) This is with and
When , the angle is an odd multiple of and is undefined.
(a)
(b) Let . Since
By the quadratic formula,
The angle is acute, so and
Replace , and choose because the answer contains only sines:
The terms cancel because they appear with opposite signs.
Expand the numerator and split the fraction into two:
(a) Expand both terms; the terms cancel:
(b) Use :
Multiply the numerator and the denominator by :
Expand the left-hand side:
Collect terms:
If , then and the equation would read
Tangent is positive in the first and third quadrants, so
Check :
Expand:
As before, gives no solution. Divide by and multiply by :
From the exact values, , and
Check:
Let . The left-hand side is , valid when :
Factorise: , so
In , tangent is positive only in the first quadrant, so each value gives one solution:
Check : and
When and , is acute and .
(a) . Then and , both positive, so is acute:
(b) The maximum value is , reached when , that is
(c) The equation becomes , so . With
( itself is outside the interval.) Adding :
(a) Expand the target form with the sine difference identity:
Match coefficients with : and . Then
( is acute because both and are positive.) So
(b) , so
Check :
(c) The minimum value is , when
(a) Let . Matching with gives and , so
So , with amplitude Pa, less than
(b) The maximum occurs when , so
(a) Use the tangent sum identity (M1):
(b) and are acute, so (R1). The only angle in
(c) From right-angled triangles with legs and (M1):
Then (M1)
(a) Show that . [4 marks] (b) Find the value of that makes as large as possible, and the maximum value of in degrees. [3 marks] (c) Find the range of distances for which . [3 marks]
(a) Let be the point on the wall level with the eye. Then and (M1), so . Using the tangent difference identity (M1):
Multiply the numerator and the denominator by :
(b) is acute and is increasing on , so
(c) when
I can explain how is derived from the distance between two points on the unit circle, and how the other identities follow.
I can find exact values such as , and .
I can find , and from given ratios, choosing signs from the quadrants.
I can derive and use .
I can prove identities that involve compound and double angles.
I can solve equations with compound angles without losing solutions by dividing.
I can write as and use it to find maximum values and solve equations.
A1
A1
3 marks
M1A1
Note: Accept
rationalising:
A1
Find the exact value of .
3 marks
Find the exact value of .
3 marks
Find the exact value of .
4 marks
Hence find the exact value of .
2 marks