Use Venn diagrams, tree diagrams, sample space diagrams and two-way tables to find probabilities of combined events, apply the addition rule, and work with mutually exclusive and independent events, with and without replacement.
Each is in the Maths AA glossary, with every other term in the subject.
The event (" and "), containing the outcomes that are in both and
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Events that cannot occur together, so and .
A grid that lists every outcome of two combined trials, such as rolling two dice, with one trial along each side.
Choosing items one after another without returning each to the population, so the probabilities for later choices change. With replacement, each item is returned and the probabilities stay the same.
A diagram of branches showing the outcomes of successive trials and their probabilities. Probabilities are multiplied along a path and added between paths.
A table of frequencies classified by two categories at once, with row and column totals, used to find probabilities of combined and conditional events.
The event (" or "), containing the outcomes that are in , in , or in both.
A diagram in which a rectangle represents the sample space and circles inside it represent events; overlapping regions show outcomes that belong to more than one event.
Most questions about chance involve more than one event: a student who studies both physics and chemistry, two cards dealt from a pack, a test that is passed at the first or second attempt. Probabilities of such combined events can be found by organising the outcomes in a diagram and then applying a small number of rules for "and", "or" and "not".
Four diagrams do this work: the Venn diagram, the sample space diagram, the two-way table and the tree diagram. Each suits a different kind of problem, and choosing the right one is often the most important step in a solution.
Two events and from the same sample space can be combined in several ways. The words "and", "or" and "not" in a question correspond to three pieces of notation borrowed from set theory.
In probability, "or" always includes the possibility of both, unless a question says otherwise (for example " or but not both"). The union therefore contains the intersection . The complement was introduced in 4.5, where complementary events were shown to satisfy
Notation | Read as | Meaning |
|---|---|---|
and | both occur | |
A Venn diagram for two events that can occur together divides the sample space into four regions. Every outcome lies in exactly one of them, so the four probabilities add up to .

Any combination of , and their complements is a union of some of these four regions. Shading the region for an expression is a reliable way to understand it, and a common short question.

When a question gives the numbers of people or items in each group, write the numbers in the regions. Always start with the overlap, then subtract to find the other regions, and finally use the total to find the number outside the circles.
The same method works with probabilities in place of numbers. The total of all regions is then instead of the number of people.
Three events give three overlapping circles and eight regions. They are filled in the same order: the centre (all three) first, then the regions where exactly two circles overlap, then the parts of each circle that belong to it alone, and finally the outside.
Adding and does not give in general, because the overlap
With equally likely outcomes, , and dividing by
The rule also shows that two events with large probabilities must overlap. If , then
Some pairs of events can never occur on the same trial. A single roll of a die cannot be both a and a ; a randomly chosen card cannot be both a heart and a club.
On a Venn diagram, mutually exclusive events are drawn as circles that do not overlap.

When two trials are combined, such as rolling two dice, every outcome is a pair. A sample space diagram lists all of the pairs in a grid, with the outcomes of one trial along the top and the other down the side. If each trial has equally likely outcomes, every cell of the grid is equally likely.
For two fair dice the grid has equally likely cells. Each cell holds the total of the two scores.

Grids are not limited to dice or to totals. Any two trials with a small number of outcomes can be combined, and each cell can hold a product, a difference, the larger score, or the pair itself.
Data collected about two characteristics at once, such as the year group of each student and how they travel to school, is summarised in a two-way table. Row and column totals make it easy to read off the probabilities of single events, of combined events and of events restricted to one group.
A school records how students in Years and travel to school.
Walk | Bus | Car | Total | |
|---|---|---|---|---|
Year 12 | ||||
Year 13 |
Part (d) is a conditional probability: the denominator is no longer the whole group of but only the group named after "given that". Probabilities of this kind can be read from any of the diagrams, and are defined formally in 4.11.
A tree diagram shows a sequence of trials, one stage after another. Each stage has a set of branches, one for each outcome, labelled with its probability. A path from the start to the end of the tree represents one combined outcome.
A bag contains red and blue counters. A counter is taken at random, its colour is noted and it is put back. A second counter is then taken. Because the first counter is replaced, the bag is the same for the second draw, and the probabilities on the second set of branches are the same as on the first.

From the tree:
The rule "multiply along a path" works because each branch after the first gives the probability of that outcome in the situation reached so far. The rule "add between paths" works because different paths are mutually exclusive: a single run of the experiment follows exactly one path.
When the first counter is not put back, the second draw is from a bag with one fewer counter, and the probabilities on the second branches depend on what happened first. This is sampling without replacement. Dealing cards, choosing people for a committee and selecting items for quality testing are all done without replacement.
Comparing the two bags shows the effect of not replacing: the probability of two reds falls from with replacement to without, because removing a red counter makes a second red less likely.
A tree does not have to be symmetrical. When an experiment stops as soon as a certain outcome occurs, only the other branches continue. Problems about repeated attempts, such as "keeps trying until successful, up to three times", produce trees of this shape.
Two events are independent when the occurrence of one does not change the probability of the other. Tossing a coin and rolling a die are independent; so are the two draws in a bag problem with replacement. The two draws without replacement are not independent, because the result of the first draw changes the contents of the bag.
For independent events, the probability that both occur is found by multiplying. This is the rule already used on every tree diagram with replacement.
The rule can be checked with a sample space. A fair coin is tossed and a fair die is rolled. There are equally likely outcomes, and only one of them is (heads, ). So
A probability "given that" an event has occurred is found by restricting attention to the outcomes in that event. In a diagram or table, this means using the size of the given group as the denominator instead of the whole sample space.
For the Physics and Chemistry Venn diagram, the probability that a student studies Physics, given that the student studies Chemistry, uses only the Chemistry students, of whom also study Physics:
Written with probabilities, this is
The formal treatment of conditional probability, its use for testing independence, and reversing conditions on a tree diagram are in 4.11.
On a tree diagram without replacement, the second-stage branches are already conditional probabilities: the branch labelled after a red counter is .
Questions on combined events often begin with a diagram to complete and then ask for several probabilities from it. Draw the diagram neatly and label it fully, because it is usually worth marks of its own and every later part depends on it.
Tree diagrams without replacement often appear with an unknown number of items. A "show that" part then asks for an equation, and the solving part follows from it.
Choosing the right diagram is often the key to a combined events question. A Venn diagram suits events that overlap within a single trial; a sample space diagram suits two trials with a small number of equally likely outcomes; a two-way table suits data classified in two ways; and a tree diagram suits trials that happen one after another, particularly when the probabilities change.
I can use the notation , , and shade the matching regions of a Venn diagram.
I can complete a Venn diagram for two or three events from frequencies or probabilities, starting from the overlap.
78 exam-style questions on this subtopic, written in the style of the IB papers. The first has its markscheme open. Counted on
Consider two events and such that , and .
Find .
2 marks
In a class of 40 students, 10 students belong to the chess club () and 16 students play in the school orchestra (). Four students belong to the chess club and also play in the orchestra.
A student is selected at random from the class.
Determine whether the events and are independent. Justify your answer.
3 marks
Find the probability that the student belongs to the chess club, given that the student does not play in the orchestra.
On one day, 250 visitors to a museum were asked whether they hired an audio guide (). Each visitor holds exactly one type of ticket: adult, student () or senior. The results are shown in the following table.
Audio guide () | No audio guide () | Total | |
|---|---|---|---|
One of 39 short multiple-choice questions on 4.6. Pick an answer to see why it's right or wrong.
Events and are mutually exclusive. Which statement must be true?
The entries of the mathematics: analysis and approaches formula booklet that 4.6 uses. Each opens in the explained booklet.
The complement is the event "not ": the outcomes that are not in .
at least one occurs |
not | does not occur |
and not | occurs but does not (" only") |
not ( or ) | neither occurs |
not ( and ) | at most one occurs |
Physics only: . Chemistry only: . Neither: .

(b)(i)
(ii) The union contains students.
(iii)
(a) Draw a Venn diagram showing the probability of each region.
(b) Find (i) (ii) (iii) (iv) .
(a) only: . only: . Outside: .

(b)(i) is " only":
(ii) .
(iii) is the region outside both circles:
(iv) is everything except the overlap, which is
(a) Draw a Venn diagram to show this information.
(b) Find the probability that a student chosen at random studies (i) none of the three languages (ii) exactly one language (iii) at least two languages.
(a) Start with in the centre. The numbers " study French and Spanish" include the who study all three, so French and Spanish only is . In the same way, French and German only is , and Spanish and German only is .
French only: . Spanish only:
The circles hold students, so

(b)(i)
(ii) Exactly one language: students.
(iii) At least two: students.
Check: .
It links four quantities, so any three of them give the fourth.
(a) and . The king of hearts is in both events, so .
Check by counting: the hearts and the other kings make cards.
(b) Substitute into the addition rule and solve.
is the complement of .
(b) Events and have and . Explain why and cannot be mutually exclusive, and write down the smallest possible value of .
(a) , and .
(b) If and were mutually exclusive, then , which is impossible because no probability exceeds
The smallest possible value of is .
(b) Totals , and occur in , and cells.
(c) The prime totals are , which occur in cells.
(d) The doubles lie on the leading diagonal: cells.
(a) Spinner goes down the side and spinner along the top. There are equally likely outcomes.
(b)(i) The odd products are , so of the products are even.
A product is odd only when both scores are odd, which is a quick check: odd cells.
(ii) The products greater than are , and .
Total |
(b) Read the single cell: .
(c) Year 12 has students and walkers number , but the Year 12 walkers are in both groups.
(d) "Given that the student walks" restricts attention to the walkers, of whom are in Year 12.

(b)(i)
(ii) Two paths, RB and BR.
(iii) The complement of "at least one red" is "both blue".
(b) Add the three "pass" paths.
Alternatively, the only way not to pass is to fail three times: .
(b) A fair die is rolled three times. Find the probability that all three scores are even.
(a) Multiply, because the events are independent.
Then use the addition rule.
(b) The rolls are independent, and on each.
(a) Draw a Venn diagram to represent this information, in terms of where necessary. [2]
(b) Find the value of . [2]
(c) A student is chosen at random. Find the probability that the student does exactly one of the two activities. [2]
(d) Given that the student plays tennis, find the probability that the student also swims. [2]
(a) The overlap is , so tennis only is and swimming only is ; go outside. (A1 for the overlap and outside, A1 for the other regions)

(b) The four regions add up to . (M1)
(c) Exactly one activity: . (M1)
(d) Restrict to the tennis players, of whom swim. (M1 for the denominator 17)
(b) Hence find the value of . [2]
(c) Find the probability that the two balls are the same colour. [3]
(a) The first ball is red with probability . With one red ball removed, of the remaining balls are red. (M1 for multiplying along the path)
Multiply both sides by .
(b) Factorise. (M1)
The number of balls is positive, so . (A1)
(c) There are red and blue balls. Same colour means RR or BB. (M1 for adding two paths)
I can apply and find any one of its quantities from the other three.
I can recognise mutually exclusive events and use for them.
I can use sample space diagrams and two-way tables to find probabilities.
I can draw a tree diagram for trials with and without replacement, multiply along paths and add between them.
I can use for independent events, and explain how independence differs from mutual exclusivity.
I can find a "given that" probability from a Venn diagram, table or tree.
A1
Find .
2 marks
correct substitution into (M1)
A1
Find .
2 marks
(A1)
Note: Follow through from their answers to parts (a) and (b).
2 marks
Adult |
48 |
72 |
120 |
Student () | 75 |
Senior | 22 | 33 | 55 |
A visitor is selected at random from these 250 visitors.
Given that , find the value of and the value of .
2 marks
Find the probability that the visitor holds a student ticket, given that the visitor hired an audio guide.
2 marks
Determine whether the events and are independent. Justify your answer.
3 marks