Find where a line meets a plane, the line of intersection of two planes and the intersection of three planes, interpret each case geometrically, and calculate angles between lines and planes and between two planes.
Each is in the Maths AA glossary, with every other term in the subject.
The acute angle between two intersecting planes, equal to the acute angle between their normal vectors.
The line common to two non-parallel planes. Its direction vector is perpendicular to both normals, for example .
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Three or more planes that all contain the same line, like the pages of a partly open book.
Lines and planes in space meet in a small number of ways, and each way corresponds to a particular kind of solution of a set of linear equations. A laser beam hitting a screen, the shadow of a pole on sloping ground, the ridge where two roof faces meet and the corner where three walls meet are all intersections of lines and planes. The same calculations give the angles involved, such as the pitch of a roof or the angle at which a ray strikes a surface.
A line and a plane in three dimensions are related in one of three ways. The direction vector of the line and the normal of the plane decide which.
Relationship | Condition | Points in common |
|---|---|---|
Line meets the plane at one point | Exactly one | |
Line lies in the plane |
If , the line is perpendicular to the normal, so it runs parallel to the plane: it either lies in it or stays a fixed distance away. Otherwise the line crosses the plane exactly once.

The quickest method uses the Cartesian equation of the plane and the parametric equations of the line:
Write the line as ,
If the plane is given in vector form, convert it to Cartesian form first (3.17). The linear equation in step 2 has the form , which is why the scalar product decides the case: if it is non-zero there is exactly one ; if it is zero the equation reads
When the coefficient of cancels, the outcome depends on the constant terms, so the remaining equation must be read carefully.
The same reasoning answers questions with an unknown constant. A line parallel to the plane can be moved into the plane by choosing its starting point correctly.
Over short distances, the rays of sunlight are parallel straight lines, and a small area of ground is close to a plane. The shadow of a point is where the ray through it meets the ground.
The angle between a line and a plane is the angle between the line and its projection onto the plane (its "shadow" when light shines along the normal). It is always between and .

The scalar product gives the angle between the line's direction and the normal , which is . Since
The modulus makes positive, so is between and whichever way and
Two planes are either parallel or they meet in a straight line. Their normals decide which:
If and are parallel, the planes are parallel. They are the same plane if one equation is a multiple of the other (for example
The direction follows from the vector product (3.16). The line lies in the first plane, so its direction is perpendicular to ; it also lies in the second plane, so its direction is perpendicular to . A vector perpendicular to both normals is

There are two standard methods. Both need one point on the line; the first finds the direction with the vector product, the second gets the direction automatically.
Method 1 (vector product and a point). Find . Then find one point on both planes: set one coordinate (often ) equal to and solve the two plane equations for the other two coordinates.
Method 2 (introduce a parameter). Set one variable equal to a parameter, for example , and solve the two equations for and in terms of . The result is the parametric form of the line.
The angle between two planes is measured in a plane perpendicular to their line of intersection, where both planes are seen edge-on as lines. Turning one plane onto the other turns its normal onto the other normal by the same amount, so the angle between the planes equals the angle between the normals (or its supplement).

The modulus gives the acute angle. Two planes actually form two angles, and , and in a context the obtuse one is sometimes the one that matters.
In a roof, the line of intersection of two faces is the ridge, and the angle with a horizontal plane is the pitch. The angle inside the roof space is the obtuse angle between the faces, which shows why the context must decide which of the two angles is wanted.
Three planes can meet at a single point, along a line, or not have any point in common at all. Each case matches a type of solution of the system of three linear equations formed by the three plane equations (1.16).
The table lists every arrangement. In the diagrams of the last four, the planes are drawn edge-on: each plane contains a direction pointing straight out of the page, so it is seen as a line.
Arrangement | Solutions of the system | Normals |
|---|---|---|
Meet at a single point | One (unique) solution | Not all parallel to one plane |
Sheaf: all contain one line | Infinitely many, one parameter | All perpendicular to the common line |
All three planes the same | Infinitely many, two parameters | All parallel; equations are multiples |
Triangular prism: meet in pairs in three parallel lines | No solution | All perpendicular to one direction; no two parallel |
Two parallel planes cut by the third | No solution | Exactly two parallel |
Three parallel planes (at least two distinct) | No solution | All parallel |
Two coincident planes cut by the third | Infinitely many: a line | Two parallel, from equations that are multiples |

The sheaf and the triangular prism look alike in algebra: in both, elimination leaves an equation with all coefficients zero. In a sheaf the last equation is (consistent, infinitely many solutions); in a prism it is with (inconsistent, no solutions). In a prism each pair of planes still meets in a line, but the three lines are parallel and never meet.
A system with a unique solution can be solved by elimination or directly with a graphic display calculator (GDC). When the GDC reports no unique solution, elimination by hand shows whether there are infinitely many solutions or none, and the normals then identify the arrangement.
Another way to see the result: and meet in the line
These questions combine every result on lines and planes, and the parts often depend on each other. Each answer can be checked by substituting it back into the original equations.
When a question says "the system has infinitely many solutions" or "the planes meet in a line", the condition is that the third equation adds no new information. That gives two conditions (one from a point, one from the direction), which is why two unknowns such as and can be found.
I can find where a line meets a plane by substituting the line's parametric equations into the plane's Cartesian equation.
I can tell from and a point whether a line meets a plane, lies in it or is parallel to it.
I can calculate the angle between a line and a plane using sine, not cosine.
I can decide whether two planes are parallel, coincident or meet in a line, and find the line of intersection by either method.
I can find the acute (and, where relevant, obtuse) angle between two planes using their normals.
I can solve three plane equations and interpret the result as a point, a sheaf, a triangular prism or parallel planes.
I can find parameter values that make three planes meet at a point, in a line or not at all.
33 exam-style questions on this subtopic, written in the style of the IB papers. The first has its markscheme open. Counted on
The points , and form the triangular base of a pyramid. The vertex of the pyramid is the point .
Find
The planes and have equations
The plane has vector equation
One of 28 short multiple-choice questions on 3.18. Pick an answer to see why it's right or wrong.
A line with direction meets a plane with normal . Which gives the angle between the line and the plane?
The entries of the mathematics: analysis and approaches formula booklet that 3.18 uses. Each opens in the explained booklet.
Every point of the line |
Line is parallel to the plane | and no point of the line is in the plane | None |
Substitute into . This gives a linear equation in .
Solve for and substitute back into the line to find the point.
A general point of is . Substitute into :
The point is . Check in
Both lines have direction , and . So each line is either in or parallel to it.
: substituting gives
: substituting gives
(a) , so the direction of is perpendicular to the normal of . The line is parallel to the plane (or lies in it), whatever is.
(b) Substitute the general point :
The terms cancel, as expected. The equation holds for every exactly when , so lies in when
(a) The ray through is , with general point . Substitute into the ground plane:
The shadow of the top is at . Check: .
(b) The base of the pole, , lies on the ground (), so the shadow runs from to . Its length is
and , so
A horizontal plane has normal
If the normals are not parallel, the planes meet in a line, called the line of intersection.
Method 1. The direction is
For a point, put : and . Adding gives
Method 2. Put . Then and
The direction is
Check the direction against both normals: and .
(a) The direction of the ridge is
which is parallel to : the ridge is horizontal. Adding the two equations gives , so , and then . The ridge is
(b) The horizontal plane has normal . For the first face,
(c) The normals give
Eliminate in two different ways. : . : , so , that is .
From , . Substituting:
The planes meet at the single point . Check in :
(a) Find the values of for which the system has a unique solution. (b) Find the values of and for which the system has infinitely many solutions, and describe the arrangement of the planes. (c) Describe the arrangement of the planes when and .
Add the first two equations to eliminate : . Subtract this from the third equation:
(a) If , then
(b) If and , the last equation is , which holds for every . There are infinitely many solutions, forming the line
(c) If and , the last equation is
(a) Substitute into :
The point is . Check: .
(b) ,
(c) Direction:
A point: with , and , so
(d)
(e) For the three planes to meet in a line, must contain the line from (c). The point must satisfy :
3 marks
, A1
attempt to use the vector product formula M1
Hence find the area of triangle ABC.
2 marks
M1
A1
Find the Cartesian equation of the plane that contains A, B and C.
2 marks
normal , substituting A: M1
A1
The line passes through V and is perpendicular to .
Write down a vector equation of .
1 mark
A1
The line meets at the point F.
Find the coordinates of F.
3 marks
substituting the components of into the equation of M1
A1
A1
Hence find the volume of the pyramid.
3 marks
height A1
volume M1
A1
Find .
2 marks
Verify that the point lies on both and
The planes and meet in the line . Hence find a vector equation for
The plane contains the point and is perpendicular to .
Find the Cartesian equation of
The line meets at the point R.
Find the coordinates of R.
3 marks
Find the shortest distance from Q to .
2 marks
The point is the reflection of Q in the line .
Find the coordinates of .
2 marks
Find a vector that is normal to .
2 marks
Hence find the Cartesian equation of .
2 marks
Find the acute angle between and the plane with equation .
3 marks
1 mark
2 marks
2 marks